Solution :
Faulty electrical connects = P(A) = 0.80
Mechanical defects = P(B) = 0.92
Mechanical defects are related to loose keys = P(C/B) = 0.27
Improper assembly = P(D/B) = 0.73
Defective wires = P(E/A) = 0.35
Improper connections = P(F/A) = 0.13
Poorly welded wires = P(G/A) = 0.52
Now, the probability due to loose keys = 0.27 x 0.92 = 0.2484
Improperly connected = 0.13 x 0.80 = 0.1040
Poorly welded wires = 0.52 x 0.80 = 0.4160
So, the probability that a failure is due to improperly connected or poorly welded wires = 0.1040 + 0.4160
= 0.5200
0.3 * (-(2 1/6))) + 0.35 = -0.3
That's how I got it.
Answer:
20) yes
21) -1
22) 1
23) -4
Step-by-step explanation:
Answer:
84
Step-by-step explanation:
6 times 7 is 42
42 times 2 is 84
Answer:
$13.12 per hour
Step-by-step explanation:
Take the total pay and divide by the number of hours
$282.08/21.5 hours
$13.12 per hour
