Interesting :0 did it rain that much-
Remember,
sin = op/hyp
cos = adj/hyp
tan = op/adj
For question 3 it would be B and C, because the adjacent side of angle x is 12, the hypotenuse is 37, and cos = adj/hyp. Also, the opposite side of angle z is 12, and the hypotenuse is 37, and sin = op/hyp. So both answers would be 12/37. You would do the same with question 4.
For 5, you would do the same thing. It would be D because you can only take the sin of angle 24, and x is a side. the opposite of 24 is x and the hypotenuse is 11, so sin 24 would be x/11. It is the same for problem 6.
Answer:
2H2S (g) + 3O2 (g) → 2H2O (l) + 2SO2 (g)
Calculate ΔH° from the given data. Is the reaction exothermic or endothermic?
ΔH°f (H2S) = -20.15 kJ/mol; ΔH°f (O2) = 0 kJ/, mol; ΔH°f (H2O) = -285.8 kJ/mol; ΔH°f (SO2) = -296.4 kJ/mol
Simple....
3x-10(x+2)=13-7x
Just solve for x.....
3x-10x-20=13-7x
-7x-20=13-7x
+7x +7x
-20=13
NO SOLUTION.
Thus, your answer.
6^5 = 6•6•6•6•6
x^7 = x•x•x•x•x•x•x
x^5 = x•x•x•x•x
5^6 = 5•5•5•5•5•5