Putting a = 6 and b= 3/2 in eqn. (1) the required equation is:-
x /6 + 2.y/3 = 1. or, x + 4y = 6. Answer.
Answer:
-2, -5
Step-by-step explanation:
h2 + 7h + 10 = 0
h^2 +7h + 10 = 0
h^2 +2h +5h + 10 = 0
h(h+2) + 5(h+2) = 0
h+2 = 0 or h+5 = 0
h = -2 or h = -5
Answer:
Arithmetic sequence states that a sequence of numbers such that the difference between the consecutive terms is constant.
it is given by:
where a is the first term , n is the number of term and d is the common difference.
Given the series: 
here, Common difference(d) = 5
First term(a) = 49
by definition we have;
For nth term

= 5n + 44
To write the series using summation notation for 14 terms
Summation symbol 
The series for 14th terms is given by;

Answer:
No, the graph is only increasing while the student rides his bike, rides the bus, and walks. It is stays the same while he waits for the bus and when the bus stops to let him off.
Step-by-step explanation: