Question

One length of a rectangular garden lies along a patio wall.​ However, the rest of the garden is enclosed by 32 feet of fencing. If the length of the garden is twice its​ width, what is the area of the​ garden?

Answer 1

Answer:

128 square feet

Step-by-step explanation:

Let the perimeter of the rectangular garden be expressed as 2(L+W)

L = length of the garden

W = width of the garden

If the length of the garden is twice its ​ width then L = 2W; W = L/2

P = 2(L+L/2)

Since the perimeter is L + 32 (One length of a rectangular garden that lies along a patio wall and the rest of the garden is enclosed by 32 feet of fencing.)

Substituting in the formula above:

32+L = 2(L+L/2)

32+L = 2L+L

32 = 2L

L = 16 feet

Since L = 2W

W = L/2 = 16/2

Width = 8 feet

Area of the garden = Length × Width

Area of the garden = 16×8

Area of the garden = 128 square feet