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2 years ago

Maxden wanted to measure the length of the objects below.

Mathematics

1 answer:

Sonja [21]2 years ago

3 0

A : inches
B : centimeters
C: feet
D: inches

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Which of the following would be an acceptable first step in simplifying the expression

krek1111 [17]

Answer: A

Step-by-step explanation: Because it can be simplified twice.

7 0

1 year ago

Five members of the computer club site to buy used computer dividing up the cost equally later three new members join a club of

BartSMP [9]

The computation shows that the price of the used computer is $75.

<h3>How to compute the price?</h3>

From the information given, it should be noted that there are 5 members before the new members joined and $15 was given to each member.

Therefore, the price of the used computer will be:

= $15 × 5

= $75

The price of the used computer is $75.

Learn more about computations on:

brainly.com/question/4658834

#SPJ1

7 0

1 year ago

Who started the problem correctly? The problem form is (-5) - (-1 3/4).

Veronika [31]

Answer:

Shane started the problem correctly

Step-by-step explanation:

We are given problem (-5) - (-1 3/4).

Mariah started the problem as (-5) + 1 - 3/4

Shane started the problem as (-5) + 1 + 3/4

We need to find who started the problem correctly.

The problem should be started by converting the mixed fraction into improper fraction i,e

$-5-(-1\frac{3}{4})\\=-5-(-1-\frac{3}{4} )\\=-5-(-\frac{7}{4})$

Now we will solve bracket by multiplying -1 with term inside the bracket i.e

$=-5+\frac{7}{4}$

$= \frac{-13}{4}$

Let's compare both the procedures now:

Mariah:

$(-5) + 1 - \frac{3}{4}$

$=(-5) - \frac{1}{4}$

$=\frac{-21}{4}$

Therefore, Mariah did not start the problem correctly.

Shane:

$(-5) + 1 + \frac{3}{4}$

$= -5 + \frac{7}{4}$

$= \frac{-13}{4}$

Therefore, Shane started the problem correctly.

6 0

2 years ago

Approximate f by a Taylor polynomial with degree n at the number a. Step 1 The Taylor polynomial with degree n = 3 is T3(x) = f(

MAVERICK [17]

Answer:

If you center the series at x=1

$T_3(x) = e^2 + 4e^2 (x-1)+10(x-1)^2 + \frac{56}{3} e^2(x-1)^3 + R(x)$

Where $R(x)$ is the error.

Step-by-step explanation:

From the information given we know that

$f(x) = e^{2x^2}$

$f'(x) = 4x e^{2x^2}$ (This comes from the chain rule )

$f^{(2)}(x) = 4e^{2x^2} (4x^2+1)$ (This comes from the chain rule and the product rule)

$f^{(3)}(x) = 16xe^{2x^2}(4x^2 + 3)$ (This comes from the chain rule and the product rule)

If you center the series at x=1 then

$T_3(x) = e^2 + 4e^2 (x-1)+10(x-1)^2 + \frac{56}{3} e^2(x-1)^3 + R(x)$

Where $R(x)$ is the error.

3 0

3 years ago

6/x-8=2/x+6 how do i solve this

lutik1710 [3]

6/(x-8)=2/(x+6)
times both sides by (x-8)(x+6)
6(x+6)=2(x-8)
distribute
6x+36=2x-16
minus 2x both sides
4x+36=-16
miinus 36 both sides
4x=-52
divide both sides by 4
x=-13

8 0

3 years ago