Answer:
S= z (y-x)/(x+y)
Step-by-step explanation:
Lets the speed of high speed train = u
Lets the regular speed train = v
We know that
Distance = Speed x time
For high speed train
z = u .x
u= z/x ----------1
For regular speed train
z = v .y
v = z/y -------------2
Both are traveling in opposite direction so relative speed
Vr = z / x+ z /y
Lets in time t they will meet
z = (z / x+ z /y) t
t= xy/ (x+y)
Lets take distance cover by high speed train is m when it moves A to B and speed cover by regular train is n when it is moving B to A.They meet at time t.
m = u .t
m = z / x .xy/ (x+y)
m = zy/ (x+y) -----------3
n = v .t
n = z / y .xy/ (x+y)
n = zx/ (x+y) -----------4
From equation 3 and 4
So
m - n= zy/ (x+y) - zx/ (x+y)
S= z (y-x)/(x+y)
Option a is correct.
Answer:
A and B
Step-by-step explanation:
A because there are 3 terms and B because the variables are x,y,z
Hope this helps!
Answer:
y=2/9x-1/3
Step-by-step explanation:
since line h is parallel to line g, this means that line h has the same slope as line g.
line h's slope would be 2/9.
to find the y-intercept, plug (-3, -1) into the equation y=2/9x+b. -3 will represent x and -1 will represent y:
y=2/9x+b
-1=2/9(-3)+b
Then, solve for b:
-1=2/9(-3)+b
-1=-6/9+b
b=-1/3
so, the equation for line g is: y=2/9x-1/3
Answer:
"16c"
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Answer:
i think 18
Step-by-step explanation:
i guess
2×9=18
3×6=18
9×2=18
