A 2 haploid cells
hope it helps
Answer:
0.28
Explanation:
This allele has incomplete dominance and analysis indicated a phenotypic distribution of 600M, 4000MN, 400N.
Using p+q = 1
Where q is the frequency of the N allele-
400N/5000 = 0.08 is the genotypic frequency out of 5000 in total - q²
Thus the frequency of the allele N is √q² = √0.08 = 0.28
A becAuse that can affect our oxygen.
The answer would be B, as scientists obviously don't know everything and theories can be changed if proven wrong.
A. P,A,E.
It first tRNA enters the p site. The rest of the tRNA enters through the a site. And leave through the e site. The first tRNA will remain in the p site, building the polypeptide chain until it hits a stop codon