Amino acids that have the possibility of participating in hydrogen bonds with suitable partners are those that have hydrophilic polar side chains.
Answer:
a.The phenotypic proportions obtained after having the genotypes are 50% marbled seeds, 25% spotted and dotted seeds since they are codominant, 25% spotted seeds.
b. Taking into account the F1 genotypes in the previous point, the expected phenotypes for the first crossing are 100% marbled seeds and for the second crossing 100% dotted seeds.
Explanation:
Let's suppose:
Marbled allele: M
Spotted allele: S
Dotted allele: D
Allele for Clear: C
a. Because both crosses were between homozygous parents, the entire F1 genotype is the same.
For the first crossing the descendants have the MS genotype, and for the second crossing the descendants have the DC genotype. It is enough to make a Punnett square to obtain the different combinations of genotypes between the crossing of MS and DC.
Neutrons
The atomic mass is the weight of the protons and neutrons in the nucleus.
For this, you need to use Punnett squares.
You know the genotype of the parents, and for the cross, you need to separate into two alleles, both genes.
AABBCc divided like ABC and ABc.
Aabbcc divided like Abc and abc.
Now you can cross them, and all probabilities will be:
AABbCc, AaBbCc, AABbcc and AaBbcc
So, you could say 25% of the offspring will be AaBbCc, 25% AaBbcc, 25% AABbCc, and 25% AABbcc
Hey there!
The correct answer would be - C.
Hope this helps!
