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3 years ago

K is the midpoint of Line JL, JL=4x-2 and JK=7. find X

1 answer:

7 0

X=4. If k is the midpoint then JK is equal to KL. Since JK is 7 then KL is also 7 meaning JK is 14. JK is represented by the expression 4x-2 so you just set that expression equal to 14 and solve for x. Hope this helped!

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How do you integrate <br><img src="https://tex.z-dn.net/?f=%283x%5E%7B2%7D%20%20%2B%203%29%20%5E%7B3%7D%20" id="TexFormula1" tit

Phoenix [80]

Answer:

Since i don't know what formula is mentioned. I just used the easiest way to solve :)

Step-by-step explanation:

$(3x^2 + 3)^3 = (3x^2)^3 + 3^3 + 3((3x^2)^2)(3) + 3(3x^2)(3^2)$

$= 27x^6 + 27 + 3(9x^4 \times 3) + 3(3x^2 \times 9)\\\\=27x^6 + 27 + 81x^4 + 81x^2\\\\=27x^6 + 81x^4 + 81x^2 + 27\\\\$

$\int\limits {(3x^2+3)^3} \, dx = \int\limits {27x^6 + 81x^4+81x^2 + 27} \, dx$

$= \frac{27}{7}x^7 + \frac{81}{5}x^5+\frac{81}{3}x^3 + 27x +C\\\\= \frac{27}{7}x^7 + \frac{81}{5}x^5+27x^3 + 27x +C\\\\$

8 0

3 years ago

1,023 + _____ = 1,400

denpristay [2]

Answer: 377

1,400 - 1,023 = 377

1,023 + 377 = 1,400

Step-by-step explanation: easy

5 0

3 years ago

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Im stuck on this question i need help

Korolek [52]

I think it’s one half 1/2

4 0

3 years ago

It’s not 0.615 , or 0.75 or the one shown in the picture

Dafna1 [17]

$2.40714$

1) Let's evaluate that expression, given that a=4.9, b=-7, and c=-0.5

$\begin{gathered} a^3\div b^2+c^3 \\ (4.9)^3\div(-7)^2+(-0.5)^3= \\ \frac{4.9^3}{\left(-7\right)^2+\left(-0.5\right)^3} \\ \\ \frac{4.9^3}{48.875} \\ \\ \frac{117.649}{48.875} \\ \\ 2.40714 \end{gathered}$

Note that we have rewritten it as a fraction so that we can easily operate. Also, we have applied here the PEMDAS order of operations, prioritizing the exponents.

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1 year ago

Sketch the graph of 5x+7y=35, include the intercepts

zhenek [66]

Slope intercept form: y= −5 7 x+5

The graphing points would be (0,5)(7,0)

7 0

3 years ago

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