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2 years ago

10

A prairie dog left its burrow 5 feet underground and started digging deeper into the ground. It digs straight down at a constant

rate of 2
feet per minute.
How long does it take the prairie dog to reach 13 feet underground?
Enter your answer in the box
min

Willing to give Brainliest No Links

1 answer:

SpyIntel [72]2 years ago

7 0

Building and solving an equation to model the situation, it is found that it takes 4 min for the prairie dog to reach 13 feet underground.

Initially, the dog is 5 feet underground.

Each minute, the dog goes 2 more feet underground.

Hence, the underground height of the dog after t seconds is given by:

$h(t) = 5 + 2t$

The time it takes for the dog to reach 13 feet underground is <u>t for which h(t) = 13</u>, hence:

$h(t) = 5 + 2t$

$13 = 5 + 2t$

$2t = 8$

$t = \frac{8}{2}$

$t = 4$

It takes 4 min for the prairie dog to reach 13 feet underground.

A similar problem is given at brainly.com/question/25290003

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