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Doss [256]
3 years ago
13

In the first propagation step of the bromination of 2,3-dimethylbutane, the newly formed Br radicals react with the molecules of

2,3-dimethylbutane. Give the major products formed by the first propagation step including both organic and inorganic products. Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. Include all free radicals by right-clicking on an atom on the canvas and then using the Atom properties to select the monovalent radical.

Chemistry
1 answer:
Bess [88]3 years ago
8 0

Answer:

See explanation

Explanation:

When the bromine free radical attacks 2,3-dimethylbutane, two free radicals may result. One of them is primary (formed by attack on then end -CH3 group) the other is secondary.

Recall that the order of stability of free radicals is tertiary > secondary > primary > methyl.

Hence the secondary free radical is more thermodynamically stable hence it is the major free radical formed in the first propagation step.

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A 27.5 −g aluminum block is warmed to 65.9 ∘C and plunged into an insulated beaker containing 55.5 g water initially at 22.1 ∘C.
Wittaler [7]

Answer:

The final temperature of aluminium ≈ 26.32 °C

Explanation:

<u>Step 1:</u> explain the problem

A 27.5 −g aluminum block is warmed to 65.9 ∘C and plunged into an insulated beaker containing 55.5 g water initially at 22.1 ∘C.

<u>Step 2:</u> Data given

We will use the formule : Q = mcΔT

with Q = heat transfer ( J)

with m = mass of the substance (g)

with c = specific heat ( J/g °C)

with ΔT = change in temperature ( in °C or K)

mass of aluminium = 27.5g

mass of water = 55.5g

specific heat of aluminium = 0.900J/g °C

specific heat of water = 4.186 J/g °C

initial temperature of aluminium T1= 65.9 °C

initial temperature of water T1 =  22.1 °C

final temperature of water and aluminium = TO BE DETERMINED

<u>Step 3:</u> Calculate the initial temperature

To find the final temperature, we have to use the  following formule:

-(Mass of aluminium) * (caluminium)*(ΔT)) = (Mass of water) *(cwater)*(ΔT)

-27.5g (0.900)(T2 - 65.9) = 55.5g (4.184j/g °C) (T2- 22.1)

-24.75*(T2-65.9) = 232.212 *(T2-22.1)

-24.75T2 + 1631.025 = 232.212T2 -5131,8852

-256.962 T2 = -6762.9102

T2 = 26.32 °C

The final temperature of aluminium ≈ 26.32 °C

6 0
3 years ago
What properties you can observe or measure?
Advocard [28]
We can observe physical properties of elements and compounds without changing the substance.

Examples of physical properties: Density, color, boiling point, state of matter, appearance: dull or shiny, etc. 

But we can also observe and measure chemical properties by reacting a substance with something else. For example, like mixing baking soda and vinegar together. The vinegar reacts with the baking soda and produces carbon dioxide: a new substance. 

Some examples of chemical properties: Flammability, amount of heat that is released during combustion, toxicity (how much damage it causes to other organisms), radioactivity, and ability to oxidize (when you have metal that becomes rusty looking).
4 0
4 years ago
What is the fourth quantum number of the 3p electron in aluminum,
jeka94

Explanation:

here's the answer to your question

8 0
3 years ago
They dump large amounts of rainwater that causes flooding. *
IgorC [24]
Answer =Tsunamis because they flood places and areas
3 0
3 years ago
Read 2 more answers
A compound is 12.7% Al, 19.7% N, and 67.6% O. Determine its emperical formula.
gizmo_the_mogwai [7]

Answer:

AlN₃O₉

Explanation:

Assume that you have 100 g of the compound.

Then you have 12.7 g Al, 19.7 g N, and 67.6 g O.

1. Calculate the <em>moles</em> of each atom

Moles of Al = 12.7 × 1/26.98 = 0.4707 mol Al

Moles of N = 19.7 × 1/14.01    =  1.406   mol N

Moles of O = 67.6 × 1/16.00  = 4.225   mol O

2. Calculate the <em>molar ratios</em>.

Al: 0.4707/0.4707 = 1

N: 1.406/0.4707    = 2.987

O: 4.225/0.4707   = 8.976

3. Determine the <em>empirical formula</em>

Round off all numbers to the closest integer.

Al: 1

N: 3

O: 9

The empirical formula is AlN₃O₉.

3 0
4 years ago
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