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NemiM [27]
3 years ago
6

Peas contain 250 kJ per 100 g. You would use the equivalent of 600 g of peas if you slept for .

Chemistry
1 answer:
Romashka [77]3 years ago
4 0

Answer: 7,793 hours.

Explanation:

Let's assume you are about 150 pounds. You would use only 414 calories a night (1.7 kJ). If 250 kJ is 100 g, then 1500 kj is 600 g. So we would need 360000 calories to be eaten. You would have to sleep for about 7,793 hours.

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Sam buys a package of chips and notices that hydrogenated vegetables oil is one of the ingredients. This ingredient primarily:
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3 years ago
50 Points <br> Look at the image below
Vadim26 [7]

Answer:

B-Sucrose molecules are too large to conduct electricity in once dissolved in water.

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Explanation:

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3 years ago
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A 0.98 gram sample of a volatile liquid was heated to 348 k. the gas occupied 265 ml of space at a pressure of 0.95 atm. what is
arlik [135]

Answer:

The molecular weight is Z =  111.2 \ g/mol

Explanation:

From the question we are told that

   The mass of the sample is  m =  0.98 \  g

    The temperature is  T  =  348 K

    The volume which the gas occupied is  V  =  265 \ ml  = 265 *10^{-3} L

     The pressure is  P  =  0.95 \  atm

Generally from the ideal gas equation we have that

       PV  =  n RT

Here n is the number of moles of the gas while the R is the gas constant with value  R  =  0.0821 \ atm \cdot L  \cdot mol^{-1} \cdot K^{-1}

        n = \frac{PV}{ RT}

=>      n = \frac{ 0.95 * 265 *10^{-3} }{   0.0821 * 348}

=>      n = 0.00881 \  mol

Generally the molecular weight is mathematically represented as

          Z =  \frac{m}{n}

=>      Z =  \frac{0.98 }{0.00881}

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3 years ago
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iragen [17]
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Hope this helps! :)
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4 years ago
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Consider the equation ∆G = –nFE, where F = 9.648533289 x 104 C/mol. Given that n is the mole of e– transferred and the following
myrzilka [38]

Answer:

See explanation below.

Explanation:

In the equation  ∆G = –nFE,  E is the electromotive force ( cell potential ) in Volts.

Now in turn a Volt is defined as the potential difference that will impart one joule of energy per coulomb of charge that moves through two points.

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Therefore in terms of units the equation will give us units of Joules:

[ mol] x [C/mol] x [J/C] = [J]

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