Answer: your answer is 32/51
Step-by-step explanation:
no se pero de seguro alguien más te ayudará
I:2x – y + z = 7
II:x + 2y – 5z = -1
III:x – y = 6
you can first use III and substitute x or y to eliminate it in I and II (in this case x):
III: x=6+y
-> substitute x in I and II:
I': 2*(6+y)-y+z=7
12+2y-y+z=7
y+z=-5
II':(6+y)+2y-5z=-1
3y+6-5z=-1
3y-5z=-7
then you can subtract II' from 3*I' to eliminate y:
3*I'=3y+3z=-15
3*I'-II':
3y+3z-(3y-5z)=-15-(-7)
8z=-8
z=-1
insert z in II' to calculate y:
3y-5z=-7
3y+5=-7
3y=-12
y=-4
insert y into III to calculate x:
x-(-4)=6
x+4=6
x=2
so the solution is
x=2
y=-4
z=-1
Answer:

Step-by-step explanation:
The applicable rules of exponents are ...

Your ratio simplifies to ...

_____
Please note that simplifying the constants, -8/10 to -4/5, eliminates half the answer choices. Since exponents are only multiplied when a power is raised to a power, you can pretty much eliminate the second choice as being unreasonable. ((a^b)^c = a^(bc))
Answer:
x = 2√13.
Step-by-step explanation:
Using the Pythagoras theorem:
14^2 = x^2 + 12^2
x^2 = 14^2 - 12^2
x^2 = (14 + 12)(14 - 12) = 52
x = √52
x = √4*√13
x = 2√13.