Question

Anyone help? What is the derivative of x^2 + 2x - 4? Thanks!

Answer 1

D/dx(x² + 2x - 4) = 2x + 2

d/d (x² + 2x - 4) 

= d/dx (x²) + d/dx(2x) - d/dx(4)

= d/dx(x^2) - d/dx(2x) = 2x (due to power rule)

Replug in to equation
d/dx (2x) = 2

Take the constant out

d/dx (x) = 1

apply the common derivative

2 x 1

simplify 

2 x 1 = 2


d/dx(4) = 0

d/dx(4)

drivative of a constant = 0

= 2x + 2 - 0

Simplify:
2x + 2

2x + 2 is your answer


hope this helps

Answer 2

Let's take the derivative of each term one by 1

x^2
Apply the power rule for derivatives.
2x^(2-1) = 2x
You get 2x.

2x
Apply the power rule (x^1) and the constant multiple rule.
2 * x^(1-1) = 2 * x^0 = 2
You get 2.

-4
The derivative of a constant is 0.

Put that together and you get 2x + 2

Have an awesome day! :)