Ask question

Ask question

All categories

2 years ago

15

Anyone help? What is the derivative of x^2 + 2x - 4? Thanks!

2 answers:

Romashka [77]2 years ago

8 0

D/dx(x² + 2x - 4) = 2x + 2

d/d (x² + 2x - 4)

= d/dx (x²) + d/dx(2x) - d/dx(4)

= d/dx(x^2) - d/dx(2x) = 2x (due to power rule)

Replug in to equation
d/dx (2x) = 2

Take the constant out

d/dx (x) = 1

apply the common derivative

2 x 1

simplify

2 x 1 = 2

d/dx(4) = 0

d/dx(4)

drivative of a constant = 0

= 2x + 2 - 0

Simplify:
2x + 2

2x + 2 is your answer

hope this helps

castortr0y [4]2 years ago

4 0

Let's take the derivative of each term one by 1

x^2
Apply the power rule for derivatives.
2x^(2-1) = 2x
You get 2x.

2x
Apply the power rule (x^1) and the constant multiple rule.
2 * x^(1-1) = 2 * x^0 = 2
You get 2.

-4
The derivative of a constant is 0.

Put that together and you get 2x + 2

Have an awesome day! :)

You might be interested in

Solve for y y-(-5)=-7

romanna [79]

Y - (-5) = -7
---------------------------
Simplify
y + 5 = -7
-------------------------------------
Subtract 5 from each side
y + 5 - 5 = -7 - 5
y = -12
--------------------------------------------
y = -12 is your answer

7 0

3 years ago

Read 2 more answers

Mathematics Financial literacy

hichkok12 [17]

Answer:

$10,500

Step-by-step explanation:

since his income is b/n $50,000 and $100,000, he pays 15%, (15/100)70,000=$10,500

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%24a%2Ba%20r%2Ba%20r%5E%7B2%7D%2B%5Cldots%20%5Cinfty%3D15%24%24a%5E%7B2%7D%2B%28a%20r%29%5E%7B

riadik2000 [5.3K]

Let

$S_n = \displaystyle \sum_{k=0}^n r^k = 1 + r + r^2 + \cdots + r^n$

where we assume |r| < 1. Multiplying on both sides by r gives

$r S_n = \displaystyle \sum_{k=0}^n r^{k+1} = r + r^2 + r^3 + \cdots + r^{n+1}$

and subtracting this from $S_n$ gives

$(1 - r) S_n = 1 - r^{n+1} \implies S_n = \dfrac{1 - r^{n+1}}{1 - r}$

As n → ∞, the exponential term will converge to 0, and the partial sums $S_n$ will converge to

$\displaystyle \lim_{n\to\infty} S_n = \dfrac1{1-r}$

Now, we're given

$a + ar + ar^2 + \cdots = 15 \implies 1 + r + r^2 + \cdots = \dfrac{15}a$

$a^2 + a^2r^2 + a^2r^4 + \cdots = 150 \implies 1 + r^2 + r^4 + \cdots = \dfrac{150}{a^2}$

We must have |r| < 1 since both sums converge, so

$\dfrac{15}a = \dfrac1{1-r}$

$\dfrac{150}{a^2} = \dfrac1{1-r^2}$

Solving for r by substitution, we have

$\dfrac{15}a = \dfrac1{1-r} \implies a = 15(1-r)$

$\dfrac{150}{225(1-r)^2} = \dfrac1{1-r^2}$

Recalling the difference of squares identity, we have

$\dfrac2{3(1-r)^2} = \dfrac1{(1-r)(1+r)}$

We've already confirmed r ≠ 1, so we can simplify this to

$\dfrac2{3(1-r)} = \dfrac1{1+r} \implies \dfrac{1-r}{1+r} = \dfrac23 \implies r = \dfrac15$

It follows that

$\dfrac a{1-r} = \dfrac a{1-\frac15} = 15 \implies a = 12$

and so the sum we want is

$ar^3 + ar^4 + ar^6 + \cdots = 15 - a - ar - ar^2 = \boxed{\dfrac3{25}}$

which doesn't appear to be either of the given answer choices. Are you sure there isn't a typo somewhere?

7 0

2 years ago

3w = -27 (equation)

kotykmax [81]

W=-9

Explanation: 3w=-27

Divide 3 from -27

-27 divided by 3 = -9

5 0

2 years ago

Read 2 more answers

Graph the points (0,-2), (4,0) and (2,0). If you want to create a parallelogram, which of the following points should used for t

MariettaO [177]

( 2 , - 2 )

................

................

................

8 0

2 years ago