Answer:
2
Step-by-step explanation:
So I'm going to use vieta's formula.
Let u and v the zeros of the given quadratic in ax^2+bx+c form.
By vieta's formula:
1) u+v=-b/a
2) uv=c/a
We are also given not by the formula but by this problem:
3) u+v=uv
If we plug 1) and 2) into 3) we get:
-b/a=c/a
Multiply both sides by a:
-b=c
Here we have:
a=3
b=-(3k-2)
c=-(k-6)
So we are solving
-b=c for k:
3k-2=-(k-6)
Distribute:
3k-2=-k+6
Add k on both sides:
4k-2=6
Add 2 on both side:
4k=8
Divide both sides by 4:
k=2
Let's check:
:


I'm going to solve
for x using the quadratic formula:







Let's see if uv=u+v holds.

Keep in mind you are multiplying conjugates:



Let's see what u+v is now:


We have confirmed uv=u+v for k=2.
Distance Rate times Time
320= R 5.25
R= 60.9
R= 61 mph
Answer: 1 1/2
Step-by-step explanation:
First subtract 1 1/3 from 3 1/3 to find what is left over from her first batch of browns, 2. Then subtract 1 1/3 from 2 and get 2/3. 2/3 is 1/2 of 1 1/3, so she can make 1 1/2 more batches of brownies.
What three consecutive integers have a sum of 48? Which means that the first number is 15, the second number is 15 + 1 and the third number is 15 + 2. Therefore, three consecutive integers that add up to 48 are 15, 16, and 17.