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KatRina [158]
3 years ago
7

Please answer this question now

Mathematics
1 answer:
docker41 [41]3 years ago
5 0

Answer:

\boxed{u = 6.0}

Step-by-step explanation:

Using the cosine rule

c^2= a^2+b^2-2abCosC

Here c = u , a = 11 , b = 12 and C = 30

u^2 = 11^2+12^2-2(11)(12)\ Cos 30\\u^2 = 121+144-2(132)(0.866)\\u^2 = 265-228.6\\u^2 = 36.37

Taking sqrt on both sides

u = 6.0   (To nearest tenth)

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Answer: sin u = -5/13 and cos v = -15/17

Step-by-step explanation:

The nice thing about trig, a little information goes a long way. That’s because there is a lot of geometry and structure in the subject. If I have sin u = opp/hyp, then I know opp is the opposite side from u, and the hypotenuse is hyp, and the adjacent side must fit the Pythagorean equation opp^2 + adj^2 = hyp^2.

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Same argument for v: adj = -15,

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I am too lazy to do the remaining arithmetic, but I think we have created a way to approach all of the similar problems.

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Divide by 20

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x = -1

8 0
3 years ago
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