3 years ago

Please answer this question now

Mathematics

1 answer:

docker41 [41]3 years ago

5 0

Answer:

$\boxed{u = 6.0}$

Step-by-step explanation:

Using the cosine rule

$c^2= a^2+b^2-2abCosC$

Here c = u , a = 11 , b = 12 and C = 30

$u^2 = 11^2+12^2-2(11)(12)\ Cos 30\\u^2 = 121+144-2(132)(0.866)\\u^2 = 265-228.6\\u^2 = 36.37$

Taking sqrt on both sides

u = 6.0 (To nearest tenth)

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