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Debora [2.8K]
3 years ago
6

Use Julia’s work and finish finding the areas of the faces what is the surface area of the rectangular pyramid

Mathematics
1 answer:
hoa [83]3 years ago
6 0

Answer:

The surface area of the rectangular pyramid is SA=109.50\ m^{2}

Step-by-step explanation:

we know that

The surface area of the rectangular prism is equal to the area of the rectangular base plus the area of the four triangular faces

so

SA=(8)(5)+2[14.75]+2[\frac{1}{2}(8)(5)]

SA=40+29.50+40

SA=109.50\ m^{2}

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Which equation is equivalent to the equation 6x+9=12? A: x + 9 = 6 B: 2 x + 3 = 4 C: 3 x + 9 = 6 D: 6 x + 12 = 9
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Answer: B

Step-by-step explanation:

3 0
3 years ago
Find the distance from A(15,21) to the line 5x +2y=4. Round your answer to the nearest tenth
butalik [34]

Answer:The distance from a point to a line is

distance(ax+by+c=0,(x0,y0)) = abs(ax0+by0+c)/sqrt(a^2+b^2)

So first convert the formula for the line to standard form

5x+2y=4

5x+2y-4=0

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Step-by-step explanation:

5 0
3 years ago
A rectangle with a width of 3 units and a length of x +5
Luden [163]

Answer:

The area is 45 units squared

Step-by-step explanation:

If the rectangle's width is 3 units, and the length is 5 times then:

5 x 3 = 15

So the length is 15 units

The area is length times width

15 x 3 = 45

The area is 45 units squared

7 0
3 years ago
I don't get it and I have tried it multiple ways
jasenka [17]

9514 1404 393

Answer:

  9350 m²

Step-by-step explanation:

There are several ways you can go at this. Here are 3 of them:

  1. along an extension of the lower right vertical edge, divide the figure into a rectangle and a right triangle.
  2. between the upper left corner and the inside corner at lower right draw a diagonal line to divide the figure into a trapezoid and a triangle.
  3. subtract the area of the trapezoid at the right from the area of the bounding rectangle

__

The relevant formulas for area are ...

  rectangle: A = LW . . . . . . . . . . . length times width

  trapezoid: A = (1/2)(b1 +b2)h . . . b1, b2 are the bases, h is the height

  triangle: A = (1/2)bh . . . . . . . . . . . b is the base, h is the height

__

Here's what those computations look like:

1. rectangle: 60m wide by 80 m high = 4800 m².

  right triangle: base 190-60 = 130 m; height = 80-10 = 70 m.

     area = (1/2)(130 m)(70 m) = 4550 m²

  figure area = 4800 m² +4550 m² = 9350 m² . . . . area of figure

__

2. The trapezoid has bases of 80 m and 10 m, and a height of 60 m. Its area is ...

  A = (1/2)(80 m +10 m)(60 m) = 2700 m²

The triangle has a base of 190 m and a height of 80-10 = 70 m. Its area is ...

  A = (1/2)(190 m)(70 m) = 6650 m²

Then the total area is 2700 m² +6650 m² = 9350 m² . . . total area

__

3. The bounding rectangle is 190 m by 80 m, so its area is ...

  A = LW = (190 m)(80 m) = 15200 m²

The (negative) trapezoid at right has bases of 10 m and 80 m, and a width of 190-60 = 130 m. Its area is ...

  A = (1/2)(10 m +80 m)(130 m) = 5850 m²

The area of the figure is the difference between these:

  figure area = 15200 m² -5850 m² = 9350 m² . . . figure area

7 0
3 years ago
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