The point G on AB such that the ratio of AG to GB is 3:2 is; G(4.2, 2)
How to partition a Line segment?
The formula to partition a line segment in the ratio a:b is;
(x, y) = [(bx1 + ax2)/(a + b)], [(by1 + ay2)/(a + b)]
We want to find point G on AB such that the ratio of AG to GB is 3:2.
From the graph, the coordinates of the points A and B are;
A(3, 5) and B(5, 0)
Thus, coordinates of point G that divides the line AB in the ratio of 3:2 is;
G(x, y) = [(2 * 3 + 3 * 5)/(2 + 3)], [(2 * 5 + 3 * 0)/(2 + 3)]
G(x, y) = (21/5, 10/5)
G(x, y) = (4.2, 2)
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Answer:
<em>We</em><em> </em><em>can</em><em> </em><em>say</em><em> </em><em>that</em>
<em> </em>3x + x + 8 = 32
<em>So</em><em>:</em><em> </em>
3x + x + 8 = 32
4x = 32 - 8
4x = 24
x = 24/4
<em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>6</u></em>
Answer:
k=5
Step-by-step explanation:
for every one unit on the x, the y goes up five. So, the ratio is 5:1 or five.
Answer:
I think its 12.3 years
Step-by-step explanation:
a fifth of 775 is 155 and 155 x 12.3 = 1850
