Lets change "16" by its to 16/1 .. since nothing can't help support 16 by itself when it is going into 7/10
Now that we change that ... your problem becomes 7/10 × 16/1
7/10 × 16/1 = 11 1/5
Because
7(16) / 10(1) = 112/10
Now lets go. to how we solve the for the answer
112/10 = 11 1/5
☺
Answer:
FOIL: 
(3x + 5y)(3x+5y)
F: 3x*3x
O: 3x*5y
I: 5y*3x
L: 5y*5y
Step-by-step explanation:
Answer:
Step-by-step explanation:
<u>Firstly we'll factorize the terms:</u>
45x³ = 3 * 3 * 5 * x * x * x
24x² = 2 * 2 * 2 * 3 * x * x
16x = 2 * 2 * 2 * 2 * x
<u>The factor which is common in all three terms is:</u>
= x
Hence GCF = x
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Givens
Let the number of students in the class be x
Let the number of pieces of gum she gave out be 3x
Equation
3x + 8 = 168 This will not work out evenly. Let's try x - 1. The reason for that is because she may not give out anything to herself.
3(x - 1) + 8 = 168 This doesn't work either.
Well we have to choose. It's a rounding problem.
3x + 8 = 168 Subtract 8 from both sides.
3x = 168 - 8 Combine
3x = 160 Divide by 3 on both sides.
x = 160 / 3
x = 53.333333333
Since that can't be, we could say there were 53 students.
3x
