Answer:
BM=CM bc of the definition of midpoint
AB =AC bc of the def of an isosceles triangle
and angle B = angle D becasur corresponding parts
Step-by-step explanation:
3rd option.
at least shows that the number can be equal to 2, and also that 2 should be the smallest possible value of the number.
Integers are closed under subtraction.
Best Answer: 2 LiCl = 2 Li + Cl2
mass Li = 56.8 mL x 0.534 g/mL=30.3 g
moles Li = 30.3 g / 6.941 g/mol=4.37
the ratio between Li and LiCl is 2 : 2 ( or 1 : 1)
moles LiCl required = 4.37
mass LiCl = 4.37 mol x 42.394 g/mol=185.3 g
Cu + 2 AgNO3 = Cu/NO3)2 + 2 Ag
the ratio between Cu and AgNO3 is 1 : 2
moles AgNO3 required = 4.2 x 2 = 8.4 : but we have only 6.3 moles of AgNO3 so AgNO3 is the limiting reactant
moles Cu reacted = 6.3 / 2 = 3.15
moles Cu in excess = 4.2 - 3.15 =1.05
N2 + 3 H2 = 2 NH3
moles N2 = 42.5 g / 28.0134 g/mol=1.52
the ratio between N2 and H2 is 1 : 3
moles H2 required = 1.52 x 3 =4.56
actual moles H2 = 10.1 g / 2.016 g/mol= 5.00 so H2 is in excess and N2 is the limiting reactant
moles NH3 = 1.52 x 2 = 3.04
mass NH3 = 3.04 x 17.0337 g/mol=51.8 g
moles H2 in excess = 5.00 - 4.56 =0.44
mass H2 in excess = 0.44 mol x 2.016 g/mol=0.887 g
Answer:
218 students purchased tickets at the dance.
Step-by-step explanation:
Let,
x be the number of presale tickets
y be the number of tickets sold at the dance
According to given statement;
x+y=334 Eqn 1
18x+24y=7320 Eqn 2
Multiplying Eqn 1 by 18
18(x+y=334)
18x+18y=6012 Eqn 3
Subtracting Eqn 3 from Eqn 2
(18x+24y)-(18x+18y)=7320-6012
18x+24y-18x-18y=1308
6y=1308
Therefore,
218 students purchased tickets at the dance.
