Answer:
x-15
Step-by-step explanation:
Oldest = 2 times Youngest -> O = 2*Y
Middle = Youngest + 5 -> M = Y+5
All of them together is 57 -> O + M + Y = 57
So you have these three equations:
(1) O = 2*Y
(2) M = Y+5
(3) O + M + Y = 57
Now you want to reduce the number of variables. You can change the second equation to be Y = M-5 and then plug in "M-5" wherever there is currently a Y:
(4) O = 2*(M-5) = 2*M - 10
(5) O + M + (M-5) = 57
which becomes O + 2M = 62
Then you plug in the "O" equation (4) into (5) which gives you
(2M-10) + 2M = 62 which reduces to 4M = 72.
So now I know M is 18.
I can now plug that into my other equations:
(4) O = 2*18 - 10 which means O = 26.
Now I plug that into (1) from the top:
26 = 2*Y which becomes 13 = Y
So now I have O, Y, and M
Oldest is 26
Middle is 18
Youngest is 13
Reading the sentence again, you can see that this makes sense.
<h3>
Answer: x+3</h3>
==============================================================
Explanation:
Use a graphing tool like Desmos to plot y = |x+3|
See below.
The graph is a V shaped figure. The vertex is at (-3,0). The interval x > 5 is entirely to the right of this vertex. So we only focus on the right hand side of the V shape.
The line making up this right hand side is the equation y = x+3
Therefore, if x > 5 then y = |x+3| becomes y = x+3
In short, we erase the absolute value lines.
2 stops for 5 packages it's easy
