A linear equation in two variables doesn't involve any power higher than one for either variable. It has the general form Ax + By + C = 0, where A, B and C are constants. It's possible to simplify this to y = mx + b, where m = ( −A / B) and b is the value of y when x = 0. A quadratic equation, on the other hand, involves one of the variables raised to the second power. It has the general form y = ax2 + bx + c. Apart from the adding complexity of solving a quadratic equation compared to a linear one, the two equations produce different types of graphs.
Answer:
AnB = ( b, c, d ) is the answer.
Hope this will help u
Answer:
Step-by-step explanation:
We can write two equations in the two unknowns using the given relations. Let g and b represent the costs of a round of golf and a turn in the batting cage, respectively.
5g +4b = 60 . . . . . Sylvester's expense
3g +6b = 45 . . . . . Lin's expense
Dividing the second equation by 3 gives ...
g +2b = 15 ⇒ 2b = 15 -g
Substituting into the first equation, we have ...
5g +2(2b) = 60
5g +2(15 -g) = 60 . . . . . substitute for 2b
3g = 30 . . . . . . . . . subtract 30, collect terms
g = 10 . . . . . . . divide by 3
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2b = 15 -10 = 5 . . . . use the value of g to find b
b = 2.5 . . . . . . . . divide by 2
Mini golf costs $10 per round; batting cages cost $2.50 per turn.
Answer:
sister = 6 years
John=18 years
Step-by-step explanation:
A(S) + 12 = 3 * A(S), subtracting A(S) from both sides one gets 12 = 2 * A(S). Now dividing both sides by 2 we get A(S) = 12/2 = 6 . Therefore, the age of the sister is 6 years when her brother John is three times as old, that is 18 years.
