FG : (3,7)(-4,-5)
slope = (-5 - 7) / (-4-3) = -12/-7 = 12/7
y = mx + b
slope(m) = 12/7
(3,7)...x = 3 and y = 7
now we sub, we r looking for b, the y int
7 = 12/7(3) + b
7 = 36/7 + b
7- 36/7 = b
49/7 - 36/7 = b
13/7 = b
so ur equation is : y = 12/7 + 13/7.....slope = 12/7, y int = 13/7
HI : (-1,0)(4,6)
slope = (6 - 0) / (4 - (-1) = 6/5
no need to go any farther.....these lines have different slopes...and their not negative reciprocals....so there will be one solution. Answer is : neither.
i also need help on this question i have a big test tommorow this will really help me
In order to solve this, we need to select the function that meets our constraints. Since x^2 - 5 occurs when x is less than 3, and the x-value we are given is -4, we use the first function.
f(-4) = (-4)^2 - 5
f(-4) = 16 - 5
f(-4) = 11
Width of the rectangle is 14 ft
Step-by-step explanation:
- Step 1: Let the width of the rectangle be x. Then length = 8 + x. Perimeter = 72 ft.
Perimeter = 2(length + width)
72 = 2 (8 + x + x)
72 = 16 + 4x
4x = 56
x = 56/4 = 14
∴ Width of the rectangle is 14 ft
Answer:
D=6+13=19
Step-by-step explanation:
F=26+12=38
M=109-18=91
k=231-56=175
