Hi I just need points jeje
The standard deviation for the number of times an odd number is rolled is 15.8
<h3>How to determine the standard deviation?</h3>
The given parameters are:
Die = regular six-sided die
n = 1000
The probability of rolling an odd number is:
p = 1/2 = 0.5
The standard deviation is then calculated as;
![\sigma = \sqrt{np(1 - p)](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Csqrt%7Bnp%281%20-%20p%29)
This gives
![\sigma = \sqrt{1000 * 0.5 * (1 - 0.5)](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Csqrt%7B1000%20%2A%200.5%20%2A%20%281%20-%200.5%29)
Evaluate the products
![\sigma = \sqrt{250](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Csqrt%7B250)
Evaluate the root
![\sigma = 15.8](https://tex.z-dn.net/?f=%5Csigma%20%3D%2015.8)
Hence, the standard deviation is 15.8
Read more about standard deviation at:
brainly.com/question/16555520
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Answer:
1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.
Step-by-step explanation:
The order in which the teachers are chosen is not important, which means that the combinations formula is used to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.
In this question:
1 from a set of 2(Either Mrs. Vera or Mr. Jan).
3 from a set of 18 - 2 = 16. So
![C_{2,1}C_{16,3} = \frac{2!}{1!1!} \times \frac{16!}{3!13!} = 1120](https://tex.z-dn.net/?f=C_%7B2%2C1%7DC_%7B16%2C3%7D%20%3D%20%5Cfrac%7B2%21%7D%7B1%211%21%7D%20%5Ctimes%20%5Cfrac%7B16%21%7D%7B3%2113%21%7D%20%3D%201120)
1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.
When multiplying fractions, just multiply straight across
10 x 11 = 110
3 x 12 = 36
110/36 is your answer
3 1/18 is simplified mixed fraction
hope this helps