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frozen [14]
3 years ago
9

Using the following production tally, determine how many total mousetraps were produced during a shift: Quantity per package: 60

Number of packages you sealed: 41 Starting quantity in first package (from previous shift): 52 Ending quantity in your last unsealed package (leave for next shift): 24 Rejected mousetraps: 34
Mathematics
2 answers:
timofeeve [1]3 years ago
3 0
The total number of packages completed was 41 and with 60 moustraps per package so 41 x 60 = 2460. Of these, 52 traps were from the previous shift and 34 were rejects so 2460-52-34 = 2374 produced + 24 in the last unsealed package = 2374 +24 = 2398.
eduard3 years ago
3 0

The solution would be like this for this specific problem:

 

No. of Packages sealed 
= (1 for Previous Shift) + (40 for My Shift) = 41

 

Previous Shift: (60-52) 

My Shift sealed: (40x60)

My Shift unsealed: 24 
Rejected: 34 

 

Total = 8 + 2400 +24 + 34 
= 2466 

 So,  there were a total of 2,466 mouse traps that were produced during a shift.

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Answer:

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Distance = speed * time

So we have that:

Distance = 300,000,000 * 1.28 = 384,000,000  meters

In cientific notation, we need the first number to be in the interval from 1 to 10, so we have 3.84, and we have to multiply by 10^8 to reach our result, so we have:

Distance = 3.84 * 10^8 meters

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3 years ago
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x intercept is (3,0)

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Step-by-step explanation:

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A group pre-orders 8 tickets for a sightseeing tour, even though they don't have the money to pay for them yet. Each ticket cost
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3 years ago
Suppose a football is kicked with an initial velocity of 82 ft/sec., at an angle of
satela [25.4K]

Answer:

The position P is:

P = 87\^x + 75\^y ft     <u><em> Remember that the position is a vector. Observe the attached image</em></u>

Step-by-step explanation:

The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity s_0 is:

y(t) = y_0 + s_0t -16t ^ 2

Where y_0 is the initial height = 0 for this case

We know that the initial velocity is:

82 ft/sec at an angle of 58 ° with respect to the ground.

So:

s_0 = 82sin(58\°) ft/sec

s_0 = 69.54 ft/sec

Thus

y(t) = 69.54t -16t ^ 2

The height after 2 sec is:

y(2) = 69.54 (2) -16 (2) ^ 2

y(2) = 75\ ft

Then the equation that describes the horizontal position of the ball is

X(t) = X_0 + s_0t

Where

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X(t) = 43.45t

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X (2) = 43.45(2)\\\\X (2) = 87\ ft

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P = 87\^x + 75\^y ft

6 0
3 years ago
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