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olga55 [171]
3 years ago
13

Use the graph of the parabola to identify the domain and range of the function.

Mathematics
1 answer:
Aliun [14]3 years ago
4 0
It’s a. The range starts at 1 and goes to infinity
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Tessa shot 36 free Throws.she made 27 of them.what fraction of the free throws did she make?
frez [133]

For this case we have the following variables:

x: number of free throws that Tessa made

y: total number of free throws

We now write the relationship of free throws.

We have then:

\frac{x}{y} =  \frac{27}{36}

Simplifying the expression we have:

\frac{x}{y} = \frac{\frac{27}{3}}{\frac{36}{3}}  = \frac{9}{12}

\frac{x}{y} = \frac{\frac{9}{3}}{\frac{12}{3}}  = \frac{3}{4}

Answer:

The fraction of the free throws that she made is:

\frac{x}{y} = \frac{3}{4}

3 0
3 years ago
Read 2 more answers
Here is an equation 2(x + 9) = -15. What are three different equations that have the same solution as that equation? Show or exp
igor_vitrenko [27]

Answer: 1) 2x+18=-15

2) -33+18

Step-by-step explanation: 1) multiply the outer number by the numbers inside the parentheses : 2 times x would = 2 because x is not by itself so it would be X=1x and you are multiplying 2x1 which = 2 and add the variable x so it would be 2×, and same with 18, you multiply 9x2 which =18 and thats how i got 2x+18 doesnt matter if i havent found the x yet because we already know what it equals to which is -15... 2) X=16.5 so to check we do 2×-16.5 which = -33 and add 18 it = -15

(IM NOT SURE ABOUT THE THRID ONE )

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%7B%28%5Cfrac%7B4%7D%7B3%7D%29%20%5E%7B-1%7D%20-%20%28%5Cfrac%7B1%7D%7B4%7D%20%29%5E%7B-1%7D%2
neonofarm [45]

Step-by-step explanation:

(4/3)–1 = 3/4 and (1/4)–1 = 4/1

now we have,

(3/4 - 4)–1 = (-13/4)–1

= -4/13

7 0
3 years ago
How would I get a answer?
tresset_1 [31]

Answer:

0.07kg

Step-by-step explanation:

1kg = 1000g

so grams/1000 =kg

70/1000 = 0.07kg

3 0
3 years ago
Find the value of 0.34 multiply by 9
prohojiy [21]
3.06 is the correct answer (;
4 0
3 years ago
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