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Hoochie [10]
3 years ago
8

Round 23.23 to the nearest whole number

Mathematics
2 answers:
Nastasia [14]3 years ago
5 0
If the digits after the decimal place are below 50 (1-49) you round down, but if the number is 50-99, you round up. In this case, you would be rounding down, because 23<50. so the answer is 23. I hope my explanation proved helpful and helped you understand :)
Hunter-Best [27]3 years ago
4 0
Since the .23 is lower than 4 the whole number 23 STAYS THE SAME.

23.0
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Kate wants to buy a bike that costs $250. She has $40 saved. She will also do 5 days of yard work earning $38 for each day. Will
Alex Ar [27]
Unfortunately, Katie will be $20 short

She has $40
Plus the $38 x 5 she will be earning which is $190
$190+$40 is $230

Looks like Kate needs one more day of hard work to get her bike ; )
4 0
3 years ago
Read 2 more answers
If g(x)=3x-11, what is x is g(x)=289
Liula [17]

Answer:x=100

Step-by-step explanation:

Since you know that g(x)=3x-11 all you have to do is substitute that into g(x)=289. So you get 3x-11=289. To get x you have to add 11 on both sides.

3x-11=289

+11 +11

----------------

3x = 300

Divide 3 on both sides to get x by itself

3x =300

---- -------

3 3

x=100

8 0
3 years ago
6) 2(n + 5) = -2<br> help i wasn’t paying attention in my google meet
bonufazy [111]

Answer: the answer is -6

2(n+5) = -2

2n + 10 = -2

2n = -2 - 10

2n = -12

2n *1/2 = -12 * 1/2 = -6

n = -6

5 0
3 years ago
Read 2 more answers
Which of the following expressions is equal to 3x^2 + 27
Kisachek [45]
Factor: 
3x^2 + 27
= 3(x^2  + 9)
Answer is 3(x^2 + 9), when factored.


A) (3x + 9i)(x + 3i)
= (3x + 9i)(x + 3i)
= (3x)(x) + (3x)(3i) + (9i)(x) + (9i)(3i)
= 3x^2 + 9ix + 9ix + 27i^2
= 27i^2 + 18ix + 3x^2



B) (3x - 9i)(x + 3i)
= (3x +  - 9i)(x + 3i)
= (3x)(x) + (3x)(3i) + ( - 9i)(x) + (- 9i)(3i)
= 3x^2 + 9ix - 9ix - 27i^2
= 27i^2 + 3x^2


C) (3x - 6i)(x + 21i)
= (3x +  - 6i)(x + 21i)
= (3x)(x) + (3x)(21i) + (- 6i)(x) + ( -6i)(21i)
= 3x^2 + 63ix - 6ix - 126i^2
=  - 126i^2 + 57ix + 3x^2






D) (3x - 9i)(x - 3i)
=  (3x +   - 9)(x +  - 3)
= (3x)(x) + (3x)( - 3i) + (- 9)(x) + ( - 9)( - 3i)
= 3x^2 - 9ix - 9x + 27i
= 9ix + 3x^2 + 27i - 9x









Hope that helps!!!

8 0
4 years ago
Read 2 more answers
X^2 + 18x + c = 25 +c
svet-max [94.6K]
Rearrange to: x^2 + 18x - 25 = 0
Then factorise (I like to do it by completing the square):
(x + 9)^2 -81 -25 = 0
(x + 9)^2 = 106
x + 9 = sqrt(106)
The sol'ns are:
x = -9 + and - sqrt(106)
7 0
3 years ago
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