In order to solve this problem, we need to use the factor and remainder theorem. Suppose we have a quadratic equation of Q(x) and a binomial x-a=0, where a is a constant such that x=a. When you substitute x=a to the quadratic equation, you use the answer as basis. Whatever the answer is, is the remainder. If the answer is zero, that means that x=a is a factor.
In this case, we substitute x=3 to the quadratic equation and equate to zero to find k.
Q(x) = x²+kx-6
Q(3) = 3²+k(3)-6 = 0
k = -1
The value of k is -1.
3p + 2c + 6b = 27
2p + 3c + 4b = 23
4p + 1c + 8b = 31
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take any 2 equations and eliminate a variable
3p + 2c + 6b = 27
4p + 1c + 8b = 31....multiply by -2
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3p + 2c + 6b = 27
-8p - 2c - 16b = - 62 (result of multiplying by -2)
--------------------add
-5p - 10b = - 35
Now take one equation, and the other equation that u have not used already, and eliminate the same variable.
4p + 1c + 8b = 31.....multiply by -3
2p + 3c + 4b = 23
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-12p - 3c - 24b = - 93 (result of multiplying by -3)
2p + 3c + 4b = 23
----------------------add
-10p - 20b = - 70
now take ur 2 equations that u eliminated the c in, and eliminate another variable
-5p - 10b = -35......multiply by -2
-10p - 20b = -70
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10p + 20b = 70 (result of multiplying by -2)
-10p - 20b = -70
-------------------add
0 = 0
when u get a result such as 0 = 0....this means there is infinite solutions to this problem
765 is the answer
1. the percent will turn on to a decimal
2. the percent is now 1.02 ( always move the decimal 2 to the left when it is a percent.
3. multipy 1.02 and 750 .
4. you sould have 765 as your answer
Answer:
25%, 1/3, .40, 3/5
Step-by-step explanation:
another way to look at this problem is, 25%, 33%, 40%, 60%
