Find the area of the surface obtained by rotating the curve y x2 0 ≤ x ≤ 2 about the y axis
1 answer:
<span>ds=<span>√<span>1+<span><span>(<span><span>dy</span><span>dx</span></span>)</span>2</span></span></span><span>dx</span>=<span>√<span>1+<span>14</span><span>(<span>x4</span>−2+<span>1<span>x4</span></span>)</span></span></span><span>dx</span></span>
<span>=<span>√<span><span>14</span><span>(<span>x4</span>+2+<span>1<span>x4</span></span>)</span></span></span><span>dx</span>=<span>√<span><span>1<span>22</span></span><span><span>(<span>x2</span>+<span>1<span>x2</span></span>)</span>2</span></span></span><span>dx</span></span>
<span>=<span>12</span><span>(<span>x2</span>+<span>1<span>x2</span></span>)</span><span>d<span>x</span></span></span>
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Step-by-step explanation: Hope this helps and good luck :))
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Answer:
it equals =204 y=12
Y = k/x where k is the constant of variation
y = 3 , x = 1.2 gives
3 = k/1.2
therefore
k = 3*1.2 = 3.6
and the required equation is
y = 3.6 / x
