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3 years ago

What related number sentence shows the commutative property of addition? 3+9=12

1 answer:

7 0

Easy all you have to do is do 3 + 9 equals 20 which we all know that because we're in high school haha anyways back to what you do 3 + 9 which equals 12 we do we have to flip it around so if you sent it around it will be 12 equals 9 + 3 no I just read it so it would be 12 plus 9 which equals 3 which we know that so you have to flip the device which is going to eat with 3 or 12 - 9 which is going to eat you 3 that's what I'm going to put with that

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G(x)=3x+3<br> h(x)=-4x+<br> (g+h)(10)

lisabon 2012 [21]

Answer: (10x + 30)

Step-by-step explanation:

1. combine like terms. -4x + 3x = -x

2. you can’t have a negative x, so you would multiply the equation (-x+3) by -1, to get (x-3).

3. (x-3)(10)... 10 • x = 10x, 10 • 3 = 30.

4. put them together, answer would be 10x + 30.

4 0

3 years ago

What is the answer 3x+15=8x

Art [367]

Answer:

3x +15 = 8x

5x = 15

x = 3

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

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Vinvika [58]

X • (2x+3)
may be answer

4 0

3 years ago

Read 2 more answers

There are 3 red and 8 green balls in a bag. If you randomly choose balls one at a time, with replacement, what is the probabilit

Kaylis [27]

So, the total number of balls is 11. We want to pick 2 red balls and 1 green ball. WLOG (since order doesnt matter here), we can say he picks red, green, red. That means on his first pick, he has a $\frac{3}{11}$ chance of picking the red ball, and he places it back in the bag. The probability of picking a green ball is $\frac{8}{11}$ , and then he places the ball back in the bag. The probability of picking the last red ball is the same as the last red ball example, and we simply multiply the probabilities together as per the multiplication rule to get:

$\frac{3}{11}\frac{3}{11}\frac{8}{11}=\frac{3*3*8}{11^3}=\frac{72}{1331}$

Now, without replacement the order does matter. He picks a red ball, a red ball then a green ball. The probability of picking the first red ball is $\frac{2}{11}$ , and the probability of picking the second red ball is $\frac{1}{10}$ and the probability of picking the green ball is $\frac{1}{9}$ . We want to multiply thm again, as per the multiplication rule like the last problem.

$\frac{2}{11}*\frac{1}{10}*\frac{1}{9}=\frac{1}{11*5*9}=\frac{1}{495}$

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3 years ago

The low temperatures of four cities for August 26, 2007 are as follows:

yarga [219]

Honolulu
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3 years ago