The sum of two consecutive integers is 105 find the integers

Mathematics

2 answers:

zzz [600]3 years ago

7 0

The integers are 52 and 53

<em><u>Solution:</u></em>

Consecutive numbers are numbers that follow each other in order. They have a difference of 1 between every two numbers

Let the two consecutive integers be x and x + 1

Given that, sum of two consecutive integers is 105

Therefore,

x + x + 1 = 105

Combine the like terms

2x + 1 = 105

2x = 105 - 1

2x = 104

Divide both sides of equation by 2

x = 52

Thus, another integer = x + 1 = 52 + 1 = 53

Thus the integers are 52 and 53

DanielleElmas [232]3 years ago

6 0

Answer:

52,53

Step-by-step explanation:

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Find the most general antiderivative of the function. (Check yo f(x) = 3^x + 7 sinh(x) F(x) = Need Help? Watch It Talk to a Tuto

egoroff_w [7]

Answer:

F(x)= $\frac{3^x}{ln(3)}$ +7cosh(x)+C

Step-by-step explanation:

The function is f(x)=3ˣ+7sinh(x), so we can define it as f(x)=g(x)+h(x) where g(x)=3ˣ and h(x)=7sinh(x).

Now we have to find the most general antiderivative of the function this means that we have to calculate $\int\ {f(x)} \, dx$ wich is the same as $\int\ {(g+h)(x)} \, dx$

The sum rule in integration states that the integral of a sum of two functions is equal to the sum of their integrals. Then,

$\int\ {(g+h)(x)} \, dx$ = $\int\ {g(x)} \, dx + \int\ {h(x)} \, dx$

1- $\int\ {g(x)} \, dx =$ $\int\ {3^x} \, dx = \frac{3^x}{ln(3)}+C$ this is because of the rule for integration of exponencial functions, this rule is:

$\int\ {a^x} \, dx =\frac{a^x}{ln(x)}$ , in this case a=3

2- $\int\ {h(x)} \, dx =$ $\int\ {7sinh(x)} \, dx =7\int\ {sinh(x)} \, dx =7cosh(x)+C$ , number seven is a constant (it doesn´t depend of "x") so it "gets out" of the integral.