Sin (tan^(-1)X)
Sin (1/tan X)
Sin (1/1 / tan X/1)
Tan X = sin X/cos X
Sin (1/1 / sin X/cos X)
Sin (1/1 • cos X/Sin X)
Sin (cos X/sin X )
Cos X.
I believe the correct answer is cos X.
Finding the square<span> root of a </span>number<span> is the inverse operation of squaring that </span>number<span>. Remember, the </span>square<span> of a </span>number<span> is that </span>number<span> times itself. The perfect squares are the squares of the whole </span>numbers<span>. The </span>square<span> root of a </span>number<span>, n, written below is the </span>number<span> that gives n when multiplied by itself.
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Answer:
x = -2
y = 6
Step-by-step explanation:
i multiplied the 1st equation by 3 and the 2nd by 5 to get the y-terms to zero out
12x + 15y = 66
+ <u>35x - 15y = -160</u>
47x = -94
x = -94/47
x = -2
substitute -2 for 'x' to solve for 'y':
4(-2) + 5y = 22
-8 + 5y = 22
5y = 30
y = 6
Answer:
x ≈ 11.7
Step-by-step explanation:
Using the cosine ratio in the right triangle
cos26° = 
= 
( multiply both sides by 13 )
13 × cos26° = x , then
x ≈ 11.7 ( to the nearest tenth )
