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3 years ago

Help me now if i get this one wrong i wont be free

Mathematics

1 answer:

jok3333 [9.3K]3 years ago

5 0

Answer: its the first one "opposite sides with equal length"

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Complete the following invoice for upholstery fabric.

Degger [83]

Answer:

a) $49.48

b) $220921.91

Step-by-step explanation:

(a) 4 yd @ $12.37 per yd = 4 x $12.37 = $49.48

(b) 271 yd @ 815.21 per yd = 271 x $815.21 = $220921.91

(c) 20% yd @ $4.95 per yd : Here the nunber of yards are missing. Hence could not be answer . However if number of yards is x . The answer would be

20% of 4.95x

(20%=0.20)

0.20 × 4.95x

8 0

3 years ago

Rewrite the following equation in slope-intercept form. 4x - y =12

Vlad [161]

Y=4x-12 hope this helps :)

3 0

3 years ago

How do solve for x in 50=-10(x+10)

Svetllana [295]

Answer:

x=-15

Step-by-step explanation:

50=-10(x+10)

Distribute 10: 50=-10x-100

Add 100 to both sides: 100+50=-10x-100+100

150=-10x

Simplify: 150/-10=-10x/-10

x=-15

4 0

3 years ago

How many solutions in 3(6x-2) = 2(9x-3)

Andreyy89

Answer:

Infinite solutions

Step-by-step explanation:

Distribute the numbers

3(6x-2) = 18x - 6

2(9x-3) = 18x - 6

18x - 6 = 18 - 6

Since both sides of the equal sign are the same, that means you can plug any number into x, and it will always be a valid answer.

7 0

3 years ago

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

<em>NO SOLUTION</em>

7 0

3 years ago