Describe how to solve the inequality 3x+4<13

Mathematics

2 answers:

gizmo_the_mogwai [7]3 years ago

8 0

Subtract 4 from both sides. Simplify 13-4 to 9. Divide both sides by 3. Simplify 9/3 to 3.
Answer: x < 3

prisoha [69]3 years ago

6 0

Ok we need to put the lettres apart and the numbers apart
3x+4-4<13-4
=3x<9
=3x\3<9\3
= x<3

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scoundrel [369]

For the first point, remember this simple rule: every exponential function $a^x$ always returns $a$ when evaluated at $x = 1$ . In fact, $a^1=a$ for every possible base $a$ .

So, we can see that the graph of the exponential passes through the point $(1,y)$ where $y$ appears to be between 1 and 2. So, the only feasible option would be $y = 1.8^x$ , because it passes throught the point $(1,1.8)$ because $f(1) = 1.8^1 = 1.8$ .

The other functions are wrong because:

$0.45^x$ would pass through $(1,0.45)$ , which would be between 0 and 1 on the y axis
$2.4^x$ would pass through $(1,2.4)$ , which would be between 2 and 3 on the y axis
$0.31^x$ would pass through $(1,0.31)$ , which would be between 0 and 1 on the y axis

As for the second question, you simply have to plug in the values: the function

$f(x) = 7^x$

means that you have to choose an input, x, and use it as exponent for 7. So, if you choose x=2, it means that you have to give exponent 2 to 7, i.e. you replace the x with the specific value, 2.

So, the expression becomes

$f(2) = 7^2 = 49$