Answer:
(-6,9,-3)
Step-by-step explanation:
-3x -y +z=6
-3x-y+3z =0
x-3z =3
Multiply the second equation by -1
-1 *(-3x-y+3z) =0*-1
3x +y -3z =0
Add this to the first equation
-3x -y +z=6
3x +y -3z =0
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0 + 0 + -2z = 6
Divide by -2
-2z/-2 = 6/-2
z = 6/-2
z=-3
Take the third equation to find x
x-3z=3
x-3(-3) = 3
x+9=3
Subtract 9 from each side
x+9-9 =3-9
x=-6
Now we need to find y
3x +y -3z =0
3(-6) +y -3(-3) =0
-18 +y +9=0
-9+y =0
Add 9 to each side
-9+9+y = 0+9
y=9
(-6,9,-3)
The answer is A because its simple reading. Are you 4? Because this is easy smh
Hi There!
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Problem #1:
At the dealership where she works, Sade fulfilled 3/10 of her quarterly sales goal in January and another 1/10 of her sales goal in February. What fraction of her quarterly sales goal had Sade reached by the end of February?
3/10 + 1/10 = 4/10
4/10 of her goal.
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Problem #2:
Shane has been monitoring his mileage. According to last week's driving log, he drove 1/10 of a mile in his car and 9/10 of a mile in his truck. How far did Shane drive last week in all?
1/10 + 9/10 = 10/10 = 1
Shane drove 1 mile.
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Problem #3:
For a class experiment, Vina's class weighed a log before and after subjecting it to termites. Before subjecting it to termites, the log weighed 7/10 of a pound. After the termites, the log weighed 3/10 of a pound. How much weight did the termites take from the log?
7/10 - 3/10 = 4/10
The termites took 4/10 pound away from the log.
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Hope This Helps :)
"Standard form" is the form ...
... ax +by = c
where a, b, c are mutually prime integers and the leading coefficient is positive. (If a ≠ 0, then it is "leading". If a = 0, then b is the leading coefficient.)
Of the choices offered, the only one that is equivalent to the given equation is ...
... -x + 6y = 5
_____
However, "standard form" requires the leading coefficient be positive, so an appropriate answer would be ...
... x -6y = -5
or
... 6y -x = 5
____
This is another one for my "broken question" file.
Yes, it is Proportional.
Y=0.25x
For example:
If x=1, y=0.25
If x=2, y=0.5
So, it is proportional.
