Question

PLEASE ANSWER HURRY THANK YOU

Answer 1

Answer: A

Step-by-step explanation: 2020 edg

Answer 2

Answer:  A. $\dfrac{6}{203}$

Step-by-step explanation:

Given : Jason bought 10 of the 30 raffle tickets for a drawing.

i.e. Total tickets = 30

Also, Number of prizes = 3

The total number of combinations of getting 3 prizes out of 30 tickets = $^{30}C_3$

The number of combinations of getting 3 prizes out of 10 tickets =$^{10}C_3$

Then, the probability that Jason will win all 3 of the prizes if once a raffle ticket wins a prize it is thrown away will be :

$\dfrac{{^{30}C_3}}{^{10}C_3}$

$=\dfrac{\dfrac{10!}{3!7!}}{\dfrac{30!}{3!27!}}=\dfrac{120}{4060}=\dfrac{6}{203}$

Hence, the probability that Jason will win all 3 of the prizes if once a raffle ticket wins a prize it is thrown away is $\dfrac{6}{203}$ .

Hence, the correct answer is A. 6/203.