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Lilit [14]
3 years ago
6

The​ architect's side view drawing of a​ saltbox-style house shows a post that supports the roof ridge. The support post is 8 ft

tall. The distance from the front of the house to the support post is less than the distance from the post to the back of the house. How far from the front of the house is the support post​ positioned?
Mathematics
1 answer:
marishachu [46]3 years ago
8 0
The side view of a saltbox-style house is an irregular pentagon. 
Let x as the distance from the house of the house to the support post
y is the distance from the post to the back of the house
We have the inequality
x < y
If the support post is 8 ft tall, then
y = 8/2 = 4 ft
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5,25,125 find 10th term
anastassius [24]

Answer:

9765625

Step-by-step explanation:

There is a common ratio between consecutive terms , that is

r = 25 ÷ 5 = 125 ÷ 25 = 5

This indicates the sequence is geometric with n th term

a_{n} = a₁r^{n-1}

where a₁ is the first term and r the common ratio

Here a₁ = 5 and r = 5 , then

a₁₀ = 5 × 5^{9} = 5 × 1953125 = 9765625

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Austen has 6 sets of 10 baseball cards Tim has three sets of 10 baseball cards how many baseball cards do they have anal
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3 years ago
The area of rectangle is ( 30x²y + 20xy ) cm² and its breadth is 10xy cm .Find its length.
emmasim [6.3K]

Step-by-step explanation:

1) The area of rectangle is ( 30x²y + 20xy ) cm² and its breadth is 10xy cm .Find its length....

= Solution ,

Length ( L ) = ?

breadth ( b ) = 10xy cm

area ( a ) = ( 30x² + 20xy )

Now ,

area ( a ) = l × b

or, ( 30x²y + 20xy ) = L × 10xy cm

or,\frac{30 {xy + 20xy}^{2} }{10xy}  = l \\

or, \: l = 3 {x}^{2 - 1}  + 2cm

\boxed{\sf{l = (3x+2)cm}}

2) Subtract the quotient when 20x⁴y² is divided by 5x³y from the product of 2x and 3y.

= Solution,

= \frac{20 {x}^{4} {y}^{2}  }{5 {x}^{3} y}   \\

= 4xy

The product of 3x and 4y = 6xy

= 6x - 4xy

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7 0
1 year ago
At the theater, the Garcia family bought 2 adult tickets and 3 children's tickets for $44.50. The Smith family bought 3 adult ti
kondaur [170]

Answer:

Adult= $11

Children = $7.5

Step-by-step explanation:

Let x represent adult ticket and y represent children ticket

2x + 3y= 44.50........equation 1

3x + 6y= 78........equation 2

From equation 1

2x + 3y= 44.50

2x= 44.50-3y

x= 44.50-3y/2

Substitute 44.50-3y/2 for x in equation 2

3x+ 6y= 78

3(44.50-3y/2) + 6y= 78

66.75- 4.5y +6y= 78

66.75 + 1.5y= 78

1.5y= 78-66.75

1.5y= 11.25

y= 11.25/1.5

y = 7.5

Substitute 7.5 for y in equation 1

2x + 3y = 44.50

2x + 3(7.5)= 44.50

2x + 22.5= 44.50

2x = 44.50-22.5

2x= 22

x= 22/2

x= 11

Hence the price of adult ticket is $11 and the price of children ticket is $7.5

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