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3 years ago

I need help. 40x^6+16x^6

Mathematics

2 answers:

Naya [18.7K]3 years ago

8 0

Answer:

56x^6

Step-by-step explanation:

40x^6+16x^6

These are like terms, so we can add them

56 x^6

xxMikexx [17]3 years ago

7 0

Answer:

56^6

Step-by-step explanation:

when they are the same exponent

you just add the coefficients

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valkas [14]

Answer:

Angle X=30°

2x=60°

Step-by-step explanation:

X+2X=90°

3x=90°

X=90/3

X=30°

Angle X=30°

2x=60°

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3 years ago

8 7/10 - 3 4/10<br>pls help im so behind

nadezda [96]

Answer:

8 7/10 - 3 4/10 = 5.3, 5 3/10, or 53/10

5.3, 5 3/10, and 53/10 all equals to 8 7/10 - 3 4/10 :)

Step-by-step explanation:

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3 years ago

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A rectangular computer monitor is measured by the length and width of its display resolution. Three different monitors are descr

Anna [14]

Answer: Monitors A and B

Step-by-step explanation:

The similar monitors based on display resolution are those with similar ratios.

Take the ratios to their simplest forms to see which are similar.

Monitor A

= 640 : 480

= 16 : 12

= 4 : 3

Monitor B

= 800 : 600

= 8 : 6

= 4 : 3

Monitor C

= 1,280 : 800

= 32 : 20

= 8 : 5

<em>Monitors A and B are similar as they have the same display ratio. </em>

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3 years ago

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Nimfa-mama [501]

Answer:

Step-by-step explanation:

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3 years ago

The coordinates of ∆ABC are A(-3, 2), B(5, 8) & C(11, 0). Which type of triangle is ∆ABC? Select All that apply.

stepan [7]

Given:

The coordinates of ∆ABC are A(-3, 2), B(5, 8) & C(11, 0).

To find:

The type of the given triangle.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using the distance formula, we get

$AB=\sqrt{(5-(-3))^2+(8-2)^2}$

$AB=\sqrt{(8)^2+(6)^2}$

$AB=\sqrt{64+36}$

$AB=\sqrt{100}$

$AB=10$

Similarly,

$BC=\sqrt{(11-5)^2+(0-8)^2}$

$BC=\sqrt{(6)^2+(8)^2}$

$BC=\sqrt{36+64}$

$BC=\sqrt{100}$

$BC=10$

And,

$AC=\sqrt{(11-(-3))^2+(0-2)^2}$

$AC=\sqrt{(14)^2+(-2)^2}$

$AC=\sqrt{196+4}$

$AC=\sqrt{200}$

$AC=10\sqrt{2}$

Two sides of the triangle are equal, i.e., $AB=BC$ . So, the triangle is an isosceles triangle.

Sum of square of two smaller side is

$AB^2+BC^2=10^2+10^2$

$AB^2+BC^2=100+100$

$AB^2+BC^2=200$

$AB^2+BC^2=AC^2$

Using the Pythagoras theorem, we can say that the given triangle is a right triangle.

Therefore, the correct options are B and F.

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3 years ago