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Marianna [84]
3 years ago
7

A construction company was contracted to build a cylindrical storage tank with a diameter of 48 feet and height of 25 feet. Just

before construction was to begin, it was learned that a new law allows tanks to be a maximum of 9 feet in height. If the tank is redesigned to meet the law, but has the same volume, what is its new diameter?
Mathematics
1 answer:
Mrrafil [7]3 years ago
8 0
V=hpir^2
d/2=r

so, at first, diameter is 48ft
48/2=24ft is radius
height is 25ft

so volume=25pi24^2 or 14400pi cubic feet

max of 9ft

if we want 9ft height
find r
hmm

14400pi=9pir^2
divide both sides by 9pi
1600=r^2
sqrt both sides
40=r
2r=d
2(40)=80=d

the new diameter is 80ft
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2 years ago
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DIA [1.3K]
Answer:  The dimensions are:   " 1.5 mi.  ×  ³⁄₁₀  mi. " .
_______________________________________________
             { length = 1.5 mi. ;  width =  ³⁄₁₀  mi. } .
________________________________________________
Explanation:
___________________________________________
Area of a rectangle:

A = L * w ; 

in which:  A = Area = (9/20) mi.² ,
                L = Length = ?
                w = width = (1/5)*L = (L/5) = ?
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  A = L * w ;  we want to find the dimensions; that is, the values for
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Plug in our given values:
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     → (9/20) = (L/1) * (L/5) = (L*L)/(1*5) = L² / 5 ;
   
          ↔  L² / 5  = 9/20 ;
 
            →  (L² * ? / 5 * ?) = 9/20 ?    

                →     20÷5 = 4 ;  so; L² *4 = 9 ;
 
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                   →  Divide EACH side of the equation by "4" ;
           
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Let us check our answers:
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