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3 years ago

W to 2nd power equals 16

2 answers:

6 0

The answer is four... i had to write it out instead of plainly stating 4. hope you get it correct. goodluck . la la al ala la al mla

kow [346]3 years ago

6 0

W to the second power means

W x W = 16

simply, you take the square root of both sides

the square root of W x W is W. so

W= the square root of 16

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Solve each equation 3x^2=80

Lapatulllka [165]

Answer:

$x = \frac{4\sqrt{15}}{3}, x = \frac{-4\sqrt{15}}{3}$

$x = \frac{\pm4\sqrt{15}}{3}$

Step-by-step explanation:

Hello!

Use the quadratic formula: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

First, let's convert our equation to standard form of a Quadratic: ax² + bx + c = 0

3x² = 80

3x² - 80 = 0

Note, thats the value of b will be 0, as there is no "bx"

Now, solve:

$x = \frac{-(0) \pm \sqrt{(0)^2 - 4(3)(-80)}}{2(3)}$ Plug in values
$x = \frac{\pm\sqrt{960}}{6}$ Simplify the radical (Discriminant)
$x = \frac{\pm8\sqrt{15}}{6}$ Pull out perfect squares
$x = \frac{4\sqrt{15}}{3}, x = \frac{-4\sqrt{15}}{3}$ Reduce factors

The solutions are $x = \frac{4\sqrt{15}}{3}, x = \frac{-4\sqrt{15}}{3}$

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3 years ago

What are the coordinates of the centroid of a triangle with vertices P(−4, −1) , Q(2, 2) , and R(2, −3) ?

Alenkasestr [34]

Answer:

$(x,y)=(0,\frac{-2}{3})$

Step-by-step explanation:

Given : Vertices of Triangle $P(x_1,y_1)=(-4,-1)$ , $Q(x_2,y_2)=(2, 2)$ and $R(x_3,y_3)=(2,-3)$

To find : Centroid of a triangle

The centroid of a triangle is the point of intersection of the three medians of the triangle.

The formula to calculate the centroid of a triangle is:

$(x,y)=(\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3})$

Where, $x_1,x_2,x_3,y_1,y_2,y_3$ are the coordinates of the centroid

Substituting the values in the formula gives us:

$(x,y)=(\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3})$

$(x,y)=(\frac{-4+2+2}{3},\frac{-1+2-3}{3})$

$(x,y)=(\frac{0}{3},\frac{-2}{3})$

Therefore, $(x,y)=(0,\frac{-2}{3})$

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