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Reika [66]
3 years ago
15

PLEASE GIVE ME ANSWERS I WILL MARK AS BRAINLIEST!

Mathematics
1 answer:
Dafna11 [192]3 years ago
7 0

Step-by-step explanation:

Please refer to the attachment

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An observer (O) is located 900 feet from a building (B). The observer notices a helicopter (H) flying at a 49° angle of elevatio
Firdavs [7]

Answer:

1035.33 feet

Step-by-step explanation:

h=900tan49

=1035.33 feet

I hope it helps

6 0
3 years ago
Someone help me multiple choice!!! <br> questions 1-5!!!
lesantik [10]

Answer:B,C,A,C.

Step-by-step explanation:

7 0
1 year ago
Va rog ajutati-ma la 5) b) si 6) dau 20 de puncte si coroana !!!
Shtirlitz [24]
Can you translate to english?
5 0
3 years ago
Will give brainliest for right answer!
Annette [7]
This is a system of equations.  We solve it by setting it up so that when we add the two equations together, one of the variables will cancel out.  We can do this by multiplying the bottom equation by 3.  This will make our system of equations equal:

3a + b + 225
-3a + 3b = 75

Now we add these two equations together, because the a terms will cancel out.

4b = 300.

We can find what b is by dividing both sides by 4.

b = 75

Next, we plug in b in one of the equations and solve for a.  You can use either equation, but I will use the second.

75 - a = 25

Subtract 25 from both sides and add a to both sides:

a = 50

So, the first option is correct.  A = 50 and b = 75.
8 0
3 years ago
Solve the following system of equations. What is one x-value of a solution? f(x)=x^(2)+7x-24 g(x)=-3x-40
Yuki888 [10]

One x- value of the solution is : -2 or -8

<h3>What is an equation?</h3>

An Equation is an algebraic statement that shows that two quantities are equal.

Analysis:

for one x-value of a solution, f(x) = g(x)

x^{2} + 7x -24 = -3x - 40

x^{2} +7x +3x -24 +40 = 0

x^{2} + 10x +16 = 0

x^{2} +8x +2x +16 = 0

x(x+8) +2(x+8) = 0

(x+2)(x+8) = 0

x = -2 or -8

In conclusion, the values of x are -2 or -8

Learn more about system of equation : brainly.com/question/14323743

#SPJ1

5 0
2 years ago
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