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Andrew [12]
3 years ago
15

A hummingbird eggs’ mass is approximately 0.374 milligram. What is the mass of 4 Hummingbird eggs?

Mathematics
2 answers:
antoniya [11.8K]3 years ago
5 0

it would be 1.496 milligrams. i hope this helps and i used a calculator

Paladinen [302]3 years ago
4 0

4 humming birds weigh about 1.496 pounds all together.

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£440 is divided between David, Mark & Henry so that David gets twice as much as Mark, and Mark gets three times as much as H
Lesechka [4]

Mark received £ 132

<em><u>Solution:</u></em>

Given that £440 is divided between David, Mark & Henry

Let "d" be the share of david

Let "m" be the share of mark

Let "h" be the share of henry

Total amount is 440

Therefore,

share of david + share of mark + share of henry = 440

d + m + h = 440 ------- eqn 1

<em><u>David gets twice as much as Mark</u></em>

d = 2m ----- eqn 2

<em><u>Mark gets three times as much as Henry</u></em>

m = 3h

h = \frac{m}{3}  ------ eqn 3

<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>

2m + m + \frac{m}{3} = 440\\\\\frac{6m + 3m + m}{3} = 440\\\\10m = 1320\\\\m = 132

Thus Mark received £ 132

8 0
3 years ago
Billy plotted −3
Darina [25.2K]

He is correct.

The further away ( to the left) from 0 a negative number is the smaller it is.

7 0
2 years ago
Read 2 more answers
25000ft to gal help me please
Alex787 [66]
25000ft=187012.99gal
4 0
3 years ago
A dog won a race at the local fair by running 5 1/4 miles exactly 2 hours . At this constant rate , how long does it take it to
coldgirl [10]

Answer:

2.4 hours

Step-by-step explanation:

6 3/10 divided by 5 1/4 is 1.2. So 6 3/10 is 1.2 times more than 5 1/4. We then take the 1.2 and multiply it by 2 hours because we need to find what's 1.2 times more than 2 hours. So then you get 2.4 hours.

3 0
2 years ago
If log a = x and log b = y, then log (ab2) equals
mylen [45]

Answer:

The answer for log(ab²) is x + 2y.

Step-by-step explanation:

You have to apply Logarithm Law,

log(a)  +   log(b) \:  ⇒ \:  log(a \times b)

log( {a}^{n} )  \: ⇒ \: n log(a)

In this question, you have to seperate it out :

log(a {b}^{2} )  =  log(a)  +  log( {b}^{2} )

log( {b}^{2} )  = 2 log(b)

let \:  log(a)  = x

let log(b)  = y

log(a {b}^{2} )  =  log(a)  + 2 log(b)

log(a {b}^{2} )  = x + 2y

3 0
3 years ago
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