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rjkz [21]
3 years ago
7

Write an equation of the line that is perpendicular to a line with the coordinates (-3,3) (0,1) that passes through the points (

0,-2).
Mathematics
1 answer:
ziro4ka [17]3 years ago
5 0

Hey there,

This is a two-step problem and two equations are involved in figuring out the problems.

Looking at the points you know the y-intercept of both equations but you would need to solve for the slope.

First Step:

  • \frac{0-(-3) }{1-3 } = \frac{3}{-2}

The slope of the first equation would be -\frac{3}{2} now we write it in slope intercept form and get y = -\frac{3}{2} x + 1.

Second Step:

Perpendicular lines have slopes that are the negative reciprocal of the original line. So the perpendicular line would have the slope as \frac{2}{3} .

The equation would be: y = \frac{2}{3} x - 2

Hope I helped,

Amna

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On a coordinate plane, a line goes through (0, negative 3) and (3, negative 2). A point is at (negative 4, 2).
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Answer:

Correct option: first one -> y = (1/3)x + (10/3)

Step-by-step explanation:

The linear function that represents a line is:

y = ax + b

Where a is the slope and b is the y-intercept.

First we need to find the slope of the line that goes through (0, -3) and (3, -2).

Using both points, we can find the equation of the line:

x = 0 -> y = -3

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b = -3

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3a = 1

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The parallel line needs to have the same slope as the line, so we can model the parallel line with the following equation:

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The parallel line goes through the point (-4, 2), so we have:

x = -4 -> y = 2

2 = (1/3)*(-4) + b

b = 2 + (4/3)

b = 10/3

So the equation of the parallel line is:

y = (1/3)x + (10/3)

Correct option: first one

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