Answer:

Step-by-step explanation:
Given that the figure is made up of portion of a square and a semicircle, we have;
BC ≅ AB = 6 cm
The area of semicircle BC with radius BC/2 = 3 is 1/2×π×r² = 1/2×π×3² = 4.5·π cm²
Triangle ABC = 1/2 × Area of square from which ABC is cut
The area of triangle ABC = 1/2×Base ×Height = 1/2×AB×BC = 1/2×6×6 = 18 cm²
The area of the figure = The area of semicircle BC + The area of triangle ABC
The area of the figure = 4.5·π cm² + 18 cm² =
.
Answer:


Step-by-step explanation:
Given

--- lower diameter
--- upper diameter
Solving (a): The curved surface area
This is calculated as:

Where
--- lower radius
--- upper radius
And
---- l represents the slant height of the frustrum





So, we have:




Solving (b): The volume
This is calculated as:

This gives:





I have no clue what the answer would be, I’ve worked on it for 25 minutes, I will get back to you if I figure it out :,)
3(41x+400) simplified = 123x+1200