4 years ago

Can somebody help me please!!

Mathematics

1 answer:

jok3333 [9.3K]4 years ago

6 0

That's a hard one, good luck

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Step-by-step explanation:

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3 years ago

It takes the high-speed train x hours to travel the z miles from Town A to Town B at a constant rate, while it takes the regular

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Answer:

$\Delta d =\frac{y-x}{y}*d_{Hs}\$

Step-by-step explanation:

Fist the velocity of high-speed train will be given by:

$V_{Hs} =\frac{z}{x}$

And the velocity of the regular will be given by:

$V_{R} =\frac{z}{y}$

The position equations of each movement will be given by:

$d_{Hs} =\frac{z}{x} t$

$d_{R} =z-\frac{z}{y} t$

We can get the encounter point isolating t in the first equation and reepalcing it in the second one:

First isolating:

$d_{Hs}\frac{x}{z} = t$

Second reeplacing t:

$d_{R} =z-\frac{z}{y}*d_{Hs}\frac{x}{z}$

$d_{R}=z-\frac{x}{y}*d_{Hs}\$

In the moment of the encounter the high-speed train have gone round $d_{Hs}\$ and the regular one $\frac{x}{y}*d_{Hs}\$

Then the difference between the distance traveled the high-speed train and the regular one is:

$\Delta d =d_{Hs}-\frac{x}{y}*d_{Hs}\$

$\Delta d =\frac{y-x}{y}*d_{Hs}\$

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4 years ago

There are 6 times as many dogs as cats. If the total number of dogs and cats is 21. How many dogs are there

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Answer:

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