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JulijaS [17]
3 years ago
10

An object is propelled vertically upward from the top of a​ 256-foot building. The quadratic function​ s(t) = ​-16t squared ​+ 1

92t​ + 256 models the​ ball's height above the​ ground, s(t), in​ feet, t seconds after it was thrown. How many seconds does it take until the object finally hits the​ ground? Round to the nearest tenth of a second if necessary. A. 6 seconds
Mathematics
1 answer:
Aneli [31]3 years ago
6 0

Answer: t= 13.2 seconds

Step-by-step explanation:

The quadratic function for ball's height in terms of time t is given as

s(t)= -16t² +192t + 256

Now we want to find out the time at which the ball hits the ground.

When the ball hits the ground, the height of the ball will become zero so in the above equation we can put s(t)=0

0= -16t² +192t + 256

or 16t² -192t - 256 = 0

Solving this quadratic equation, we have

t= 13.211 and t= -1.211

Since time can't be negative so

t= 13.2 seconds

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6 0
4 years ago
The unit cost, in dollars, to produce tubs of ice cream is $18 and the fixed cost is $11610. The price-demand function, in dolla
Trava [24]

Answer:

Step-by-step explanation:

Let x represent the number of tubs of ice cream that was produced.

The unit cost, in dollars, to produce tubs of ice cream is $18 and the fixed cost is $11610. This means that the total cost of producing x tubs of ice cream would be

C(x) = 18x + 11610

The price-demand function, in dollars per tub, is p(x)=374-2x.

The revenue function is product of the output by the price function

R(x) = x × p(x) = xp(x)

R(x) = x(374 - 2x) = 374x - 2x²

The profit function P(x) = R(x) - C(x)

Therefore,

P(x) = 374x - 2x² - (18x + 11610)

P(x) = 374x - 2x² - 18x - 11610

P(x) = - 2x² + 374x - 18x - 11610

P(x) = - 2x² + 356x - 11610

At the break even point,

Revenue = total cost.

Therefore,

374x - 2x² = 18x + 11610

2x² + 18x - 374x + 11610 = 0

2x² - 356x + 11610 = 0

Dividing through by 2, it becomes

x² - 178x + 5805 = 0

Applying the general formula for quadratic equations,

x = [- b ±√(b² - 4ac)]/2a

x = [- - 178 ±√(-178² - 4 × 1 × 5805)]/2 × 1

x = [178 ±√(31684 - 23220)]/2

x = [178 ±92]/2

x = (178 + 92)/2 or (178 - 92)/2

x = 135 or x = 43

Therefore, the quantity for the smallest break-even point is 43.

4 0
3 years ago
use the general slicing method to find the volume of The solid whose base is the triangle with vertices (0 comma 0 )​, (15 comma
lyudmila [28]

Answer:

volume V of the solid

\boxed{V=\displaystyle\frac{125\pi}{12}}

Step-by-step explanation:

The situation is depicted in the picture attached

(see picture)

First, we divide the segment [0, 5] on the X-axis into n equal parts of length 5/n each

[0, 5/n], [5/n, 2(5/n)], [2(5/n), 3(5/n)],..., [(n-1)(5/n), 5]

Now, we slice our solid into n slices.  

Each slice is a quarter of cylinder 5/n thick and has a radius of  

-k(5/n) + 5  for each k = 1,2,..., n (see picture)

So the volume of each slice is  

\displaystyle\frac{\pi(-k(5/n) + 5 )^2*(5/n)}{4}

for k=1,2,..., n

We then add up the volumes of all these slices

\displaystyle\frac{\pi(-(5/n) + 5 )^2*(5/n)}{4}+\displaystyle\frac{\pi(-2(5/n) + 5 )^2*(5/n)}{4}+...+\displaystyle\frac{\pi(-n(5/n) + 5 )^2*(5/n)}{4}

Notice that the last term of the sum vanishes. After making up the expression a little, we get

\displaystyle\frac{5\pi}{4n}\left[(-(5/n)+5)^2+(-2(5/n)+5)^2+...+(-(n-1)(5/n)+5)^2\right]=\\\\\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}(-k(5/n)+5)^2

But

\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}(-k(5/n)+5)^2=\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}((5/n)^2k^2-(50/n)k+25)=\\\\\displaystyle\frac{5\pi}{4n}\left((5/n)^2\displaystyle\sum_{k=1}^{n-1}k^2-(50/n)\displaystyle\sum_{k=1}^{n-1}k+25(n-1)\right)

we also know that

\displaystyle\sum_{k=1}^{n-1}k^2=\displaystyle\frac{n(n-1)(2n-1)}{6}

and

\displaystyle\sum_{k=1}^{n-1}k=\displaystyle\frac{n(n-1)}{2}

so we have, after replacing and simplifying, the sum of the slices equals

\displaystyle\frac{5\pi}{4n}\left((5/n)^2\displaystyle\sum_{k=1}^{n-1}k^2-(50/n)\displaystyle\sum_{k=1}^{n-1}k+25(n-1)\right)=\\\\=\displaystyle\frac{5\pi}{4n}\left(\displaystyle\frac{25}{n^2}.\displaystyle\frac{n(n-1)(2n-1)}{6}-\displaystyle\frac{50}{n}.\displaystyle\frac{n(n-1)}{2}+25(n-1)\right)=\\\\=\displaystyle\frac{125\pi}{24}.\displaystyle\frac{n(n-1)(2n-1)}{n^3}

Now we take the limit when n tends to infinite (the slices get thinner and thinner)

\displaystyle\frac{125\pi}{24}\displaystyle\lim_{n \rightarrow \infty}\displaystyle\frac{n(n-1)(2n-1)}{n^3}=\displaystyle\frac{125\pi}{24}\displaystyle\lim_{n \rightarrow \infty}(2-3/n+1/n^2)=\\\\=\displaystyle\frac{125\pi}{24}.2=\displaystyle\frac{125\pi}{12}

and the volume V of our solid is

\boxed{V=\displaystyle\frac{125\pi}{12}}

3 0
3 years ago
Help with #5 please!
Dmitrij [34]
If you plug in the x and y of choice b you would see that it does not equal 18.

6(3) + 3(-1) = 18
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7 0
3 years ago
Read 2 more answers
Ruby bought a new car for £10625. She got a discount of 15% of the recommended retail
natali 33 [55]

Answer:

15/100 x 10625

Saved: 1593.75 pounds

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3 years ago
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