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Tomtit [17]
3 years ago
11

Cells are starved of energy when _ is unable to enter

Biology
1 answer:
defon3 years ago
7 0

Answer:

Here is the complete statement: Cells are starved of energy when GLUCOSE is unable to enter.

Explanation:

Glucose, which is a monosacharide is the primary source of energy for all the cells in the body of humans. Glucose is the end product that is typically obtained from the digestion of carbohydrate. After digestion, the glucose is absorbed by the small intestine and is transported into the blood. Glucose needs the enzyme insulin in order to enter the body cells. When the glucose enter the cells, the cells use it to produce energy in the form of ATP. Without energy cells can not survive.

Without the help of insulin, glucose will not be able to enter the cells and the cells will starve and start to look for other meaning of biological fuel. This may include breaking down the protein in the body to convert it to glucose for energy.

The disease condition in which glucose that is present in the blood is not able to enter the cells due to non functional insulin is called diabetes mellitus.

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❥SCIENCE SUBJECT
Fiesta28 [93]

9514 1404 393

Answer:

  • time: 1.122 seconds
  • range: 10.693 m
  • maximum height: 1.543 m

Explanation:

<u>Given</u>:

  runner is launched at 30° angle to horizontal at 11 m/s

  acceleration due to gravity is g = -9.8 m/s²

<u>Find</u>:

  runner's hang time

  runner's distance to the landing point

  runner's maximum height

<u>Solution</u>:

The (horizontal, vertical) speed components will be ...

  (11 m/s)(cos(30°), sin(30°)) = (5.5√3 m/s, 5.5 m/s)

The time of flight can be found from the height formula:

  h(t) = 1/2gt² +vt . . . . . . where v is the vertical speed at launch

The time we're concerned with is the time when h(t)=0 and t>0.

  0 = -4.9t^2 +5.5√3t = t(-4.9t +5.5√3)

The second factor is zero when ...

  t = (5.5√3)/4.9 ≈ 1.122 . . . seconds hang time

__

The distance to the landing point will be the product of horizontal speed and hang time:

  d = (5.5 m/s)(5.5√3/4.9 s) ≈ 10.693 m . . . . distance to landing

__

The maximum height can be found from the formula (based on conversion of kinetic energy to potential energy) ...

  h = v²/|2g| = (5.5 m/s)²/(2(9.8 m/s²)) ≈ 1.543 m . . . . maximum height

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Answer:

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Answer:

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Explanation:

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1 year ago
What are the three major components of a cladogram?
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