Answer:
44
Step-by-step explanation
4c + d
this is an expression and since they provided c and d it is easy to solve
c = 9 and d = 8. You need to plug in c and d into the expression to solve the problem.
4(9) + (8)
4 times 9 is 36 so it leaves you with 36 + 8
36 + 8 = 44
I hope this helps but basically the concept is just plugging in the numbers in place of the variables. For future problems plug in the numbers given where the variables are.
Answer:
B
Step-by-step explanation:
All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

Multiply both sides by <em>r</em> :

Subtract the latter sum from the first, which eliminates all but the first and last terms:

Solve for
:

Then as gets arbitrarily large, the term
will converge to 0, leaving us with

So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18
0.0018 is what is was in a decimail but i dont know what the quiestion is
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