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Maurinko [17]
3 years ago
5

a farmer notes that in a field of goats and geese there are 41 heads and 114 feet how many of each animal are there

Mathematics
1 answer:
solniwko [45]3 years ago
6 0

Answer:

There are 25 geese and 16 goats

Step-by-step explanation:

Let O represent the # of goats and E the # of geese.  Remembering that goats have four feet and geese only two, and that each animal has only one head, we can write the following equations to determine O and E:

Number of heads:  41; this is the total of the # of goat heads and the # of goose heads:  O + E = 41

(4 feet per goat)O + (2 feet per goose)E = 114 (There are a total of 114 feet)

Then we solve the following system of linear equations:

  O   +   E   =    41

 4O   +   2E  = 114

Multiplying the first equation by -2 results in -2O  - 2E  = -82.

Combining this result with the second equation, we obtain the system

 4O  +  2E  =  114

 -2O  - 2E  = -82

-------------------------------

  2O =   32

Then O = # of goats = 32/2, or 16, and so the equation O   +   E   =    41 becomes

         E  = # of geese =  41 - O (remembering that we found O to be 16), or

         E  =  41 - 16  = 25


There are 25 geese and 16 goats.

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-- 1:
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-- 2:
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-- 3:
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-- 4: 
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-- 5:
   A number greater than 10 with a 5 in the units place is a multiple
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-- 6:
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-- 7:
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-- 8:
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-- 9:
   A number greater than 10 with a 9 in the units place could be
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It CAN't have a  0,  2,  4,  5,  6,  or  8 .

The only choice that includes all of the possibilities is  'A' .

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