Ask question

Ask question

All categories

3 years ago

12

Choose the graph that matches the following system of equations: 4x + y = −1 3x + 2y = 8

2 answers:

Nadusha1986 [10]3 years ago

4 0

Umm....where is the graph?
or is it just my computer????

arlik [135]3 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

the price of the cup of coffee has dropped to 2.50 today. yesterday's price was 2.75. find the decrease percentage and round to

kiruha [24]

2.75/100=0.25/d
d=(100*0.25)/2.75
d=0.9

5 0

3 years ago

Solve the following differential equation: (1− 5 y +x) dy/dx +y= 5/x −1 .<br><br> C=

Ganezh [65]

Answer:

$y(1+x)+x-5\ln xy=C$

Step-by-step explanation:

Consider the given differential equation is

$(1-\frac{5}{y}+x)\frac{dy}{dx}+y=\frac{5}{x}-1$

$(1-\frac{5}{y}+x)\frac{dy}{dx}=\frac{5}{x}-1-y$

$(1-\frac{5}{y}+x)dy=(\frac{5}{x}-1-y)dx$

Taking all variables on right sides.

$(1-\frac{5}{y}+x)dy-(\frac{5}{x}-1-y)dx=0$

$(-\frac{5}{x}+1+y)dx+(1-\frac{5}{y}+x)dy=0$

Let as assume,

$M=-\frac{5}{x}+1+y$ and $N=1-\frac{5}{y}+x$

Find partial derivatives $\frac{\partial M}{\partial y}$ and $\frac{\partial N}{\partial x}$

$\frac{\partial M}{\partial y}=1$ and $\frac{\partial N}{\partial x}=1$

Since $\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$ , therefore the given differential equation is exact.

The solution of the exact differential equation is

$\int Mdx+\int N(\text{without x)}dy=C$

$\int (-\frac{5}{x}+1+y)dx+\int (1-\frac{5}{y})dy=C$

$yx-5\ln x+x+y-5\ln y=C$

$y+x+xy-5\ln x-5\ln y=C$

$y(1+x)+x-5(\ln x+\ln y)=C$

$y(1+x)+x-5\ln xy=C$

7 0

3 years ago

Combine and simplify the third set of terms 2+15a-2

Finger [1]

<span>2 + 15a - 2
= 15a (because 2 - 2 = 0)

hope it helps</span>

6 0

3 years ago

2.Each purse contains 8 coins. Find a rule to give the total number of coins.

Masja [62]

<u>I</u><u>f</u><u> </u><u>w</u><u>e</u><u> </u><u>h</u><u>a</u><u>v</u><u>e</u><u> </u><u>t</u><u>o</u><u> </u><u>f</u><u>i</u><u>n</u><u>d</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>t</u><u>o</u><u>t</u><u>a</u><u>l</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u> </u><u>o</u><u>f</u><u> </u><u>c</u><u>o</u><u>i</u><u>n</u><u>s</u><u> </u><u>t</u><u>h</u><u>e</u><u>n</u><u> </u><u>w</u><u>e</u><u> </u><u>c</u><u>a</u><u>n</u><u> </u><u>u</u><u>s</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>f</u><u>o</u><u>l</u><u>l</u><u>o</u><u>w</u><u>i</u><u>n</u><u>g</u><u> </u><u>rule:</u>

<u>I</u><u>f</u><u> </u><u>E</u><u>a</u><u>c</u><u>h</u><u> </u><u>P</u><u>u</u><u>r</u><u>s</u><u>e</u><u> </u><u>C</u><u>o</u><u>n</u><u>t</u><u>a</u><u>i</u><u>n</u><u>s</u><u> </u><u>8</u><u>c</u><u>o</u><u>i</u><u>n</u><u>s</u><u> </u><u>,</u><u>t</u><u>h</u><u>e</u><u>n</u><u> </u><u>w</u><u>e</u><u> </u><u>c</u><u>a</u><u>n</u><u> </u><u>f</u><u>i</u><u>n</u><u>d</u><u> </u><u>t</u><u>o</u><u>t</u><u>a</u><u>l</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u> </u><u>o</u><u>f</u><u> </u><u>c</u><u>o</u><u>i</u><u>n</u><u>s</u><u> </u><u>b</u><u>y</u><u> </u><u>m</u><u>u</u><u>l</u><u>t</u><u>i</u><u>p</u><u>l</u><u>y</u><u>i</u><u>n</u><u>g</u><u> </u><u>8</u><u> </u><u>t</u><u>o</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>o</u><u>t</u><u>a</u><u>l</u><u> </u><u>p</u><u>u</u><u>r</u><u>s</u><u>e</u>

<u>T</u><u>h</u><u>u</u><u>s</u><u>,</u>

<h3><u>R</u><u>u</u><u>l</u><u>e</u><u> </u><u>i</u><u>s</u><u> </u><u>:</u></h3>

<u>︎⠀⠀ ⠀⠀ ⠀⠀ ⠀</u><u>︎⠀⠀ ⠀⠀ ⠀</u><u>8</u><u>×</u><u>T</u><u>o</u><u>t</u><u>a</u><u>l</u><u> </u><u>N</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u> </u><u>o</u><u>f</u><u> </u><u>P</u><u>u</u><u>r</u><u>s</u><u>e</u><u>.</u>

<h2><u>─━─━─━─━─━─━─━─━─━─━─━─━─</u></h2>

4 0

2 years ago

What will be the coordinates of N after a 90° counterclockwise rotation around the origin?

USPshnik [31]

Answer:

A. (-7,-3)

D.(-3,-7) If clockwise

4 0

3 years ago