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Nutka1998 [239]

2 years ago

6

Please help each equation is a number from 1 to 6

1 answer:

Angelina_Jolie [31]2 years ago

5 0

The answers r 1, 2 and 4

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PLS HELP I DONT UNDERSTAND :( WILL GIVE BRAINLIEST !!!

vodomira [7]

the answer is c

i already done it

5 0

3 years ago

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What's the center of a circle whose equation is (x – 14)2 + (y + 21)2 = 64?

kvasek [131]

Answer:

The center of the circle is:

$\left(a,\:b\right)=\left(14,\:-21\right)$

Thus, option (2) is true.

Step-by-step explanation:

The circle equation is given by

$\left(x-a\right)^2+\left(y-b\right)^2=r^2$

here,

r = raduis

center = (a, b)

Given the equation

$\left(x-14\right)^2+\left(y+21\right)^2=64$

$\mathrm{Rewrite}\:\left(x-14\right)^2+\left(y+21\right)^2=64\:\mathrm{in\:the\:form\:of\:the\:standard\:circle\:equation}$

$\left(x-14\right)^2+\left(y-\left(-21\right)\right)^2=8^2$

comparing with the circle equation

$\left(x-a\right)^2+\left(y-b\right)^2=r^2$

Therefore, the center of the circle is:

$\left(a,\:b\right)=\left(14,\:-21\right)$

Thus, option (2) is true.

7 0

2 years ago

Arrange the entries of matrix A in increasing order of their cofactors values

givi [52]

To find the cofactor of

$A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]$

We cross out the Row and columns of the respective entries and find the determinant of the remaining $2\times 2$ matrix with the alternating signs.

$Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|$

$Ac_{11}=4\times 1- -1\times 2$

$Ac_{11}=4+ 2$

$Ac_{11}=6$

$Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|$

$Ac_{12}=-(-7\times 1- -1\times -8)$

$Ac_{12}=-(-7- 8)$

$Ac_{12}=15$

$Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|$

$Ac_{21}=-(5\times 1- 3\times 2)$

$Ac_{21}=-(5-6)$

$Ac_{21}=1$

$A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|$

$Ac_{23}=-(7\times 2 -8\times 5)$

$Ac_{23}=-(14-40)$

$Ac_{23}=26$

$A_c{31}=\left|\begin{array}{ccc}5&3\\4&-1\end{array}\right|$

$Ac_{31}=5\times -1 -4\times 3$

$Ac_{31}=-5-12$

$Ac_{31}=-17$

$A_c{33}=\left|\begin{array}{ccc}7&5\\-7&4\end{array}\right|$

$Ac_{33}=7\times 4- -7\times 5$

$Ac_{33}=28+35$

$Ac_{33}=63$

Therefore in increasing order, we have;

$Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63$

7 0

2 years ago

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Will give Branliest if you answer in the next five mins question is in the picture please hurry I'm about to get in trouble by m

Aleksandr-060686 [28]

Answer:

2.86

Step-by-step explanation:

Add all of them together to get 20, divide by the total employees so 7, you get 2.857. Round to nearest hundredth to get 2.86

4 0

2 years ago

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What's the answer to number 16?

Svet_ta [14]

You will wait 210 days. Hope this helps!

4 0

2 years ago

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